Sorting two dimensional array how to ?

[Carlos]

I have the following two dimension array:

public double[,] mData = new double[259200,3];

now I need to sort the values based on the values of third index of the
second dimension, like

[0,0]= 11
[0,2]= 22
[0,3]= 444
[1,0]=1
[1,2]=33
[1,3]=11
[2,0]=333
[2,2]=44
[2,3]= 222

I need it to be after sorting using the third (index 2) of the second
dimension

[0,0]= 1
[0,2]= 33
[0,3]= 11
[1,0]=333
[1,2]=44
[1,3]=222
[2,0]=11
[2,2]=22
[2,3]= 444

Thanks in advance for you help

[Jon Skeet [C# MVP]]

Carlos <[e-mail]> wrote:

I have the following two dimension array:

public double[,] mData = new double[259200,3];

now I need to sort the values based on the values of third index of the
second dimension, like

The way to do this is to use jagged arrays instead of rectangular ones.
Then you've got an array of arrays, and you can sort that in the same
way that you can sort any other single-dimensional array with
Array.Sort, providing an IComparer to compare elements (each element
will be an array, that you take the 3rd element of to use for
comparisons).

--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too

[Carlos]

Thanks Jon
I check the jagged array
"Jon Skeet [C# MVP]" <sk***@pobox.com> wrote in message
news:MP************************@msnews.microsoft.c om...

Carlos <[e-mail]> wrote:

I have the following two dimension array:

public double[,] mData = new double[259200,3];

now I need to sort the values based on the values of third index of the
second dimension, like

The way to do this is to use jagged arrays instead of rectangular ones.
Then you've got an array of arrays, and you can sort that in the same
way that you can sort any other single-dimensional array with
Array.Sort, providing an IComparer to compare elements (each element
will be an array, that you take the 3rd element of to use for
comparisons).

--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too