RichTextBox.selection.color

[DG]

i do:

for(int i=0; i<10; i++)
{
txtLog.Text = i.ToString() + "\r\n" + txtLog.Text;
startSelection = txtLog.SelectionStart;
lenghtSelection = txtLog.SelectionLength;
txtLog.Select(0, i.ToString().Length);

if(i%2 == 0)
{
txtLog.SelectionColor = Color.Black;
MessageBox.Show("");
}
else
{
txtLog.SelectionColor = Color.Red;
MessageBox.Show("");
}
txtLog.Select(startSelection, lenghtSelection);

}

i expect every other row to be different color but
first row get colored well, but afer new row is colored in new color, all
rows under are colored to old color

e.g:

(5th step)
black
red
red
red
red

(6th step)
red
black
black
black
black
black

when does coloring actually occur? after SelectionColor?

[C# Learner]

DG <[e-mail]> wrote:

for(int i=0; i<10; i++)
{
txtLog.Text = i.ToString() + "\r\n" + txtLog.Text;
Here, the text is written using the colour that was last set. When you set
the colour below, it continues to use that colour here.
startSelection = txtLog.SelectionStart;
lenghtSelection = txtLog.SelectionLength;
Since you just replaced all the text, the selection was just lost.
Therefore,

txtLog.SelectionStart == txtLog.SelectionLength == 0

at this point.

<snip>
txtLog.Select(startSelection, lenghtSelection);

This is equivalent to

txtLog.Select(0, 0);

(see above). However, this is also pointless for another reason: at the
top of the loop, you replace the text, whereupon these values are reset.

<snip>

Here's a working solution:

{
txtLog.Clear();
for(int i=0; i<10; i++)
{
txtLog.Select(0, 0);
txtLog.SelectionColor = i%2 == 0 ? Color.Black : Color.Red;
txtLog.SelectedText = i.ToString() + "\r\n";
}
}

[DG]

i don't quite get it, how does SelectedText property work?
it inserts new text in RichTexbox?

"C# Learner" <cs****@learner.here> wrote in message
news:1w****************@csharp.learner...

DG <[e-mail]> wrote:

for(int i=0; i<10; i++)
{
txtLog.Text = i.ToString() + "\r\n" + txtLog.Text;

Here, the text is written using the colour that was last set. When you
set
the colour below, it continues to use that colour here.

startSelection = txtLog.SelectionStart;
lenghtSelection = txtLog.SelectionLength;

Since you just replaced all the text, the selection was just lost.
Therefore,

txtLog.SelectionStart == txtLog.SelectionLength == 0

at this point.

<snip>

txtLog.Select(startSelection, lenghtSelection);

This is equivalent to

txtLog.Select(0, 0);

(see above). However, this is also pointless for another reason: at the
top of the loop, you replace the text, whereupon these values are reset.

<snip>

Here's a working solution:

{
txtLog.Clear();
for(int i=0; i<10; i++)
{
txtLog.Select(0, 0);
txtLog.SelectionColor = i%2 == 0 ? Color.Black : Color.Red;
txtLog.SelectedText = i.ToString() + "\r\n";
}
}

[C# Learner]

DG <[e-mail]> wrote:

i don't quite get it, how does SelectedText property work?
it inserts new text in RichTexbox?

If SelectionLength is 0, then it inserts the text at position
SelectionStart. If SelectionLength is greater than 0, then it replaces the
current selection.

[DG]

Thank you!
"C# Learner" <cs****@learner.here> wrote in message
news:5m**************@csharp.learner...

DG <[e-mail]> wrote:

i don't quite get it, how does SelectedText property work?
it inserts new text in RichTexbox?

If SelectionLength is 0, then it inserts the text at position
SelectionStart. If SelectionLength is greater than 0, then it replaces
the
current selection.