Message Queue Question:

[Charles Shao]

Message Queue Question:

I'm trying to make a demo for MSMQ.
I send a message(string) on client and try to receive it in a daemon(Windows
service).
Now, I get a problem:

1. When I start the service in services manager, The start event will be
time out. but in fact, the service is running and in loop "for".
What can I to for this problem.

Thanks

Charles Shao :-)

================================================== ==============
server.OnStart()
{
.....
for(;;)
{
crrMsg = Msmq1.Receive();
GlobalLog.write("Received Message:" + crrMsg.Body.ToString() + "\n" );
}
}// In fact, On start will never return .

[Willy Denoyette [MVP]]

"Charles Shao" <ad****@263.net> wrote in message
news:ew**************@TK2MSFTNGP12.phx.gbl...

Message Queue Question:

I'm trying to make a demo for MSMQ.
I send a message(string) on client and try to receive it in a
daemon(Windows
service).
Now, I get a problem:

1. When I start the service in services manager, The start event will be
time out. but in fact, the service is running and in loop "for".
What can I to for this problem.

Thanks

Charles Shao :-)

================================================== ==============
server.OnStart()
{
.....
for(;;)
{
crrMsg = Msmq1.Receive();
GlobalLog.write("Received Message:" + crrMsg.Body.ToString() + "\n" );
}
}// In fact, On start will never return .

The problem is that you need to return from OnStart within 30 seconds by
default.
So you need to spawn another thread to do the actual processing.

Willy.