by: Nicolas |
last post by:
Why does for the same code I got different result
the VB code gave me what I want why not the csharp?
Thank you for your help...
CSHARP CODE
int sx, sy;
double sdegrees;
sdegrees = (90 -...
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by: ng_mr |
last post by:
No, not a question about "banker's rounding" or whatever it's called.
I want to round a double to the nearest 100th, so I perform the
following:
// original is a double
double result =...
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by: nvphu |
last post by:
I need to use the constant M_PI. So, I insert the directive # include <math.h>.
However when compiled, there are errors : M_PI undeclared identifier.
Second, I can not use the function...
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by: Mitchell Vincent |
last post by:
Just making sure I'm not missing the boat here, but are there any
special routines for doing currency math (fixed precision stuff) in .NET?
The wonderful problems of doing math on decimals tend...
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by: Chris Davoli |
last post by:
The folllowing will round to 526, but it should round to 527. It works
correctly for all other numbers, except for this one. Does anybody know of a
bug in Math.Round?
Dim ldecWater As Decimal =...
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by: David Coleman |
last post by:
I am running VS 2003 and have applied SP1. (On WinXP SP2, .Net 1.1)
In the Command Window I get the following
? Math.Round(0.715, 2)
0.72
? Math.Round(0.725, 2)
0.72
? Math.Round(0.735, 2)...
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by: Altman |
last post by:
OK I was having rounding problems before and I didn't realize that
their was a third parameter in the round function that would tell it if
it a 5 to round up. I thought adding this would fix the...
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by: Zeng |
last post by:
Math.Round has good behavior as following:
Math.Round(3.45, 1); //Returns 3.4. The last '5' is thrown away because 4 is
even
Math.Round(3.75, 1); //Returns 3.8. The last '5' is used because '7'...
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by: =?Utf-8?B?UmVuZQ==?= |
last post by:
Hello everyone
I have a problem with Math.Round, it´s ocurring some strange:
Math.Round(12.985) = 12.98, it´s wrong. It should be: 12.99
Why?? What is the problem?
Help ME !!!!
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by: DaiOz |
last post by:
Hi guys im doing a course which includes some JavaScript and I need help with the following question please,
The code I have so far is below but I don't think its right please help as I need...
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by: DolphinDB |
last post by:
Tired of spending countless mintues downsampling your data? Look no further!
In this article, you’ll learn how to efficiently downsample 6.48 billion high-frequency records to 61 million...
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by: isladogs |
last post by:
The next Access Europe meeting will be on Wednesday 6 Mar 2024 starting at 18:00 UK time (6PM UTC) and finishing at about 19:15 (7.15PM).
In this month's session, we are pleased to welcome back...
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by: isladogs |
last post by:
The next Access Europe meeting will be on Wednesday 6 Mar 2024 starting at 18:00 UK time (6PM UTC) and finishing at about 19:15 (7.15PM).
In this month's session, we are pleased to welcome back...
|
by: jfyes |
last post by:
As a hardware engineer, after seeing that CEIWEI recently released a new tool for Modbus RTU Over TCP/UDP filtering and monitoring, I actively went to its official website to take a look. It turned...
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by: PapaRatzi |
last post by:
Hello,
I am teaching myself MS Access forms design and Visual Basic. I've created a table to capture a list of Top 30 singles and forms to capture new entries. The final step is a form (unbound)...
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by: CloudSolutions |
last post by:
Introduction:
For many beginners and individual users, requiring a credit card and email registration may pose a barrier when starting to use cloud servers. However, some cloud server providers now...
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by: Shællîpôpï 09 |
last post by:
If u are using a keypad phone, how do u turn on JavaScript, to access features like WhatsApp, Facebook, Instagram....
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by: af34tf |
last post by:
Hi Guys, I have a domain whose name is BytesLimited.com, and I want to sell it. Does anyone know about platforms that allow me to list my domain in auction for free. Thank you
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by: isladogs |
last post by:
The next Access Europe User Group meeting will be on Wednesday 3 Apr 2024 starting at 18:00 UK time (6PM UTC+1) and finishing by 19:30 (7.30PM).
In this session, we are pleased to welcome former...
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