Math.Pow() bug? - C# / C Sharp

double v = -0.17665577379401631
double f = 0.016666666666666666
Math.Pow(v, f) returns me NaN.

What should I do now?

Nov 16 '05 #1

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4999

Christoph Nahr

On 3 Dec 2004 13:41:15 -0800, bo*****@yahoo.com (Bo) wrote:

double v = -0.17665577379401631
double f = 0.016666666666666666
Math.Pow(v, f) returns me NaN.

What should I do now?

Read the documentation?
--
http://www.kynosarges.de

Nov 16 '05 #2

James Curran

"Bo" <bo*****@yahoo.com> wrote in message
news:a7**************************@posting.google.c om...

double v = -0.17665577379401631
double f = 0.016666666666666666
Math.Pow(v, f) returns me NaN.

What should I do now?

Use different numbers? f = 1/60, so you are asking for the 60th root
of v, or, what number when multiplied by itself 60 times will equal v.

But no number can, because, as 60 is even, any number raised to the 60th
power will be positive. In fact, Math.Pow is documented as refusing to
calculate the root of any negative number. The Calculator app that comes
with Windows operates the same way.

--
Truth,
James Curran
[erstwhile VC++ MVP]
Home: www.noveltheory.com Work: www.njtheater.com
Blog: www.honestillusion.com Day Job: www.partsearch.com

Nov 16 '05 #3

Bo Dong

Where?

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Nov 16 '05 #4

Mike Schilling

"Bo" <bo*****@yahoo.com> wrote in message
news:a7**************************@posting.google.c om...

double v = -0.17665577379401631
double f = 0.016666666666666666
Math.Pow(v, f) returns me NaN.

What should I do now?

Create a Complex type?

Nov 16 '05 #5

Jon Skeet [C# MVP]

Bo Dong <bo*****@yahoo.com> wrote:

Where?

In MSDN, for Math.Pow. In particular, the line which states that if x
(v in your case) is < 0, and y (f in your case) is between 0 and 1
exclusive, the result is NaN.

--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too

Nov 16 '05 #6

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