Basic C# Question

[Barry Young]

I have the following .cs file: Hope you can read the code

In the Main() I want to pass the PathName and FileName and have the
FileStream object do a read, and return it into a string.

I can get intellisense to recognize Source.ReadSourceFile, but I haven't
figured out away to pass the parameters with this call in the Main():

string Test = Source.ReadSourceFile.Read("C:\\MyFile\\", "TestDir.txt");

Here it is:

using System;
using System.IO;

namespace Source
{

/// <summary>
/// Summary description for Class1.
/// </summary>

public class ReadSourceFile
{
public string Read(string PathName, string FileName)
{
System.IO.FileStream file = new System.IO.FileStream(PathName + FileName,
System.IO.FileMode.Open, FileAccess.Read);
StreamReader sr = new StreamReader(file);
string s = sr.ReadToEnd();
return s;
}
} }

public class main
{
string Test = Source.ReadSourceFile.Read("C:\\MyFile\\", "TestDir.txt");
}

///End code here

Any help would be appreciated!

Barry

[Ansil MCAD]

hi barry ,
you can do it using

static void Main(string[] args)

The parameter of the Main method is a string array that represents the
command-line arguments. Usually you check for the existence of the arguments
by testing the Length property

if (args.Length == 0)
error "Please enter arguments"
else
access the arguments using args[0],args[1]..and so on

regards
Ansil
Dimensions
Technopark
Trivandrum
an****@gmail.com

"Barry Young" wrote:

I have the following .cs file: Hope you can read the code

In the Main() I want to pass the PathName and FileName and have the
FileStream object do a read, and return it into a string.

I can get intellisense to recognize Source.ReadSourceFile, but I haven't
figured out away to pass the parameters with this call in the Main():

string Test = Source.ReadSourceFile.Read("C:\\MyFile\\", "TestDir.txt");

Here it is:

using System;
using System.IO;

namespace Source
{

/// <summary>
/// Summary description for Class1.
/// </summary>

public class ReadSourceFile
{
public string Read(string PathName, string FileName)
{
System.IO.FileStream file = new System.IO.FileStream(PathName + FileName,
System.IO.FileMode.Open, FileAccess.Read);
StreamReader sr = new StreamReader(file);
string s = sr.ReadToEnd();
return s;
}
} }

public class main
{
string Test = Source.ReadSourceFile.Read("C:\\MyFile\\", "TestDir.txt");
}

///End code here

Any help would be appreciated!

Barry

[Barry Young]

Hi Ansil,

Keeping the same context as in my sample code, can you give me an idea how I
could change it to make it work?

Thanks!

Barry

"Ansil MCAD" <An*******@discussions.microsoft.com> wrote in message
news:E1**********************************@microsof t.com...

hi barry ,
you can do it using

static void Main(string[] args)

The parameter of the Main method is a string array that represents the
command-line arguments. Usually you check for the existence of the
arguments
by testing the Length property

if (args.Length == 0)
error "Please enter arguments"
else
access the arguments using args[0],args[1]..and so on

regards
Ansil
Dimensions
Technopark
Trivandrum
an****@gmail.com

"Barry Young" wrote:

I have the following .cs file: Hope you can read the code

In the Main() I want to pass the PathName and FileName and have the
FileStream object do a read, and return it into a string.

I can get intellisense to recognize Source.ReadSourceFile, but I haven't
figured out away to pass the parameters with this call in the Main():

string Test = Source.ReadSourceFile.Read("C:\\MyFile\\", "TestDir.txt");

Here it is:

using System;
using System.IO;

namespace Source
{

/// <summary>
/// Summary description for Class1.
/// </summary>

public class ReadSourceFile
{
public string Read(string PathName, string FileName)
{
System.IO.FileStream file = new System.IO.FileStream(PathName +
FileName,
System.IO.FileMode.Open, FileAccess.Read);
StreamReader sr = new StreamReader(file);
string s = sr.ReadToEnd();
return s;
}
} }

public class main
{
string Test = Source.ReadSourceFile.Read("C:\\MyFile\\", "TestDir.txt");
}

///End code here

Any help would be appreciated!

Barry

[Stefan Simek]

Hi,

I don't exactly understand what are you trying to do (I guess it's not
passing command-line parameters as Ansil wrote).

If you just can't get your code to compile, see inline:

"Barry Young" <yo******@insightbb.com> wrote in message
news:xPZjd.316064$wV.275593@attbi_s54...

Hi Ansil,

Keeping the same context as in my sample code, can you give me an idea how
I could change it to make it work?

Thanks!

Barry

"Ansil MCAD" <An*******@discussions.microsoft.com> wrote in message
news:E1**********************************@microsof t.com...

hi barry ,
you can do it using

static void Main(string[] args)

The parameter of the Main method is a string array that represents the
command-line arguments. Usually you check for the existence of the
arguments
by testing the Length property

if (args.Length == 0)
error "Please enter arguments"
else
access the arguments using args[0],args[1]..and so on

regards
Ansil
Dimensions
Technopark
Trivandrum
an****@gmail.com

"Barry Young" wrote:

I have the following .cs file: Hope you can read the code

In the Main() I want to pass the PathName and FileName and have the
FileStream object do a read, and return it into a string.

I can get intellisense to recognize Source.ReadSourceFile, but I haven't
figured out away to pass the parameters with this call in the Main():

string Test = Source.ReadSourceFile.Read("C:\\MyFile\\", "TestDir.txt");

Here it is:

using System;
using System.IO;

namespace Source
{

/// <summary>
/// Summary description for Class1.
/// </summary>

public class ReadSourceFile
{
public string Read(string PathName, string FileName)
Replace with: public static string Read(string PathName, string FileName)

If the function is not static, you must first instantiate an object to and
call methods on it.
{
System.IO.FileStream file = new System.IO.FileStream(PathName +
FileName,
System.IO.FileMode.Open, FileAccess.Read);
StreamReader sr = new StreamReader(file);
string s = sr.ReadToEnd();
return s;
}
} }

public class main
{
Where's the Main() method?

static void Main()
{ string Test = Source.ReadSourceFile.Read("C:\\MyFile\\",
"TestDir.txt"); }
}

I hope the rest should work OK Here is a complete code that works for me:

using System;
using System.IO;

namespace Source
{

/// <summary>
/// Summary description for Class1.
/// </summary>

public class ReadSourceFile
{
public static string Read(string pathName, string fileName)
{
using (StreamReader sr = new StreamReader(Path.Combine(pathName,
fileName)))
return sr.ReadToEnd();
}
}
}

public class main
{
static void Main()
{
string test = Source.ReadSourceFile.Read("C:\\MyFile\\",
"TestDir.txt");
}
}

Please note that it's always recommended to dispose objects that implement
the IDisposable interface. Also it's not required to create a FileStream and
then a StreamReader from it.

HTH,
Stefan
///End code here

Any help would be appreciated!

Barry

[Ansil MCAD]

hi
i got your problem now

the parameters you pass contains slashes
so use it like this

Source.ReadSourceFile.Read(@"C:\\MyFile\\", "TestDir.txt");

and make your Read method of the calss ReadSourceFile as static

public static string Read(string PathName, string FileName)

Ansil
Dimensions
Technopark
Trivandrum
an****@gmail.com


"Barry Young" wrote:

Hi Ansil,

Keeping the same context as in my sample code, can you give me an idea how I
could change it to make it work?

Thanks!

Barry

"Ansil MCAD" <An*******@discussions.microsoft.com> wrote in message
news:E1**********************************@microsof t.com...

hi barry ,
you can do it using

static void Main(string[] args)

The parameter of the Main method is a string array that represents the
command-line arguments. Usually you check for the existence of the
arguments
by testing the Length property

if (args.Length == 0)
error "Please enter arguments"
else
access the arguments using args[0],args[1]..and so on

regards
Ansil
Dimensions
Technopark
Trivandrum
an****@gmail.com

"Barry Young" wrote:

I have the following .cs file: Hope you can read the code

In the Main() I want to pass the PathName and FileName and have the
FileStream object do a read, and return it into a string.

I can get intellisense to recognize Source.ReadSourceFile, but I haven't
figured out away to pass the parameters with this call in the Main():

string Test = Source.ReadSourceFile.Read("C:\\MyFile\\", "TestDir.txt");

Here it is:

using System;
using System.IO;

namespace Source
{

/// <summary>
/// Summary description for Class1.
/// </summary>

public class ReadSourceFile
{
public string Read(string PathName, string FileName)
{
System.IO.FileStream file = new System.IO.FileStream(PathName +
FileName,
System.IO.FileMode.Open, FileAccess.Read);
StreamReader sr = new StreamReader(file);
string s = sr.ReadToEnd();
return s;
}
} }

public class main
{
string Test = Source.ReadSourceFile.Read("C:\\MyFile\\", "TestDir.txt");
}

///End code here

Any help would be appreciated!

Barry

[Philip Rieck]

You can either alter your main to create a "ReadSourceFile" object, then
call "Read' on it, or make "Read" static. The way you have it, you're
trying to call a method on a type, but the method can only be called on an
instance of that type

so for #1 change main (to call the method on an instance):
public class main
{
ReadSourceFile r = new Source.ReadSourceFile();
string Test = r.Read("C:\\MyFile\\", "TestDir.txt");
}

....
or for #2 (to make the method defined on the type, not on instance) change
ReadSourceFile to
public class ReadSourceFile
{
public static string Read(string PathName, string FileName)
{
System.IO.FileStream file = new System.IO.FileStream(PathName + FileName,
System.IO.FileMode.Open, FileAccess.Read);
StreamReader sr = new StreamReader(file);
string s = sr.ReadToEnd();
return s;
}

--
-Philip Rieck
http://philiprieck.com/blog/

-
"Barry Young" <yo******@insightbb.com> wrote in message
news:TNWjd.74110$R05.48439@attbi_s53...

I have the following .cs file: Hope you can read the code

In the Main() I want to pass the PathName and FileName and have the
FileStream object do a read, and return it into a string.

I can get intellisense to recognize Source.ReadSourceFile, but I haven't
figured out away to pass the parameters with this call in the Main():

string Test = Source.ReadSourceFile.Read("C:\\MyFile\\", "TestDir.txt");

Here it is:

using System;
using System.IO;

namespace Source
{

/// <summary>
/// Summary description for Class1.
/// </summary>

public class ReadSourceFile
{
public string Read(string PathName, string FileName)
{
System.IO.FileStream file = new System.IO.FileStream(PathName +
FileName, System.IO.FileMode.Open, FileAccess.Read);
StreamReader sr = new StreamReader(file);
string s = sr.ReadToEnd();
return s;
}
} }

public class main
{
string Test = Source.ReadSourceFile.Read("C:\\MyFile\\", "TestDir.txt");
}

///End code here

Any help would be appreciated!

Barry

[Philip Rieck]

You can either alter your main to create a "ReadSourceFile" object, then
call "Read' on it, or make "Read" static. The way you have it, you're
trying to call a method on a type, but the method can only be called on an
instance of that type

so for #1 change main (to call the method on an instance):
public class main
{
ReadSourceFile r = new Source.ReadSourceFile();
string Test = r.Read("C:\\MyFile\\", "TestDir.txt");
}

....
or for #2 (to make the method defined on the type, not on instance) change
ReadSourceFile to
public class ReadSourceFile
{
public static string Read(string PathName, string FileName)
{
System.IO.FileStream file = new System.IO.FileStream(PathName + FileName,
System.IO.FileMode.Open, FileAccess.Read);
StreamReader sr = new StreamReader(file);
string s = sr.ReadToEnd();
return s;
}

--
-Philip Rieck
http://philiprieck.com/blog/

-
"Barry Young" <yo******@insightbb.com> wrote in message
news:TNWjd.74110$R05.48439@attbi_s53...

I have the following .cs file: Hope you can read the code

In the Main() I want to pass the PathName and FileName and have the
FileStream object do a read, and return it into a string.

I can get intellisense to recognize Source.ReadSourceFile, but I haven't
figured out away to pass the parameters with this call in the Main():

string Test = Source.ReadSourceFile.Read("C:\\MyFile\\", "TestDir.txt");

Here it is:

using System;
using System.IO;

namespace Source
{

/// <summary>
/// Summary description for Class1.
/// </summary>

public class ReadSourceFile
{
public string Read(string PathName, string FileName)
{
System.IO.FileStream file = new System.IO.FileStream(PathName +
FileName, System.IO.FileMode.Open, FileAccess.Read);
StreamReader sr = new StreamReader(file);
string s = sr.ReadToEnd();
return s;
}
} }

public class main
{
string Test = Source.ReadSourceFile.Read("C:\\MyFile\\", "TestDir.txt");
}

///End code here

Any help would be appreciated!

Barry