How can I set a byte to hold the binary value 10?

[Max Adams]

How can I set a byte to hold the binary value 10?

Doing this doesn't work, I want to store the code for 10 in 1 byte of
memory.

byte encodedBytes = '10';

Doesn't compile "Too many characters in character literal"

Any thoughts?

[Morten Wennevik]

Hi Max,

Well, assuming you mean binary 10 as in decimal 2

byte encodedBytes = 2;

Or

byte encodedBytes = (byte)Convert.ToInt32("10", 2);

--
Happy Coding!
Morten Wennevik [C# MVP]

[Nicholas Paldino [.NET/C# MVP]]

Max,

If you want a general way to convert the binary representation of a
number to a byte, then use the static ToByte method on the Convert class,
like so:

// Convert "10" to a byte:
byte b = Convert.ToByte("10", 2);

The second parameter is the base to interpret the string in.

Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard.caspershouse.com

"Max Adams" <ru************@hotmail.com> wrote in message
news:uE**************@TK2MSFTNGP12.phx.gbl...

How can I set a byte to hold the binary value 10?

Doing this doesn't work, I want to store the code for 10 in 1 byte of
memory.

byte encodedBytes = '10';

Doesn't compile "Too many characters in character literal"

Any thoughts?

[Morten Wennevik]

Ignore my answer and use Nicholas' instead. No need to convert to int when ToByte has a similar overload.

Note though that you can set a byte directly to an integer value, but need to cast it to (byte) if it needs to be evaluated.

--
Happy Coding!
Morten Wennevik [C# MVP]

[Max Adams]

> How can I set a byte to hold the binary value 10?

Doing this doesn't work, I want to store the code for 10 in 1 byte of
memory.

byte encodedBytes = '10';

Doesn't compile "Too many characters in character literal"

To avoid confusion, my post should have read, how do I convert the integer
number 10 (ten) to a one byte representation.

[Jon Skeet [C# MVP]]

Max Adams <ru************@hotmail.com> wrote:

To avoid confusion, my post should have read, how do I convert the integer
number 10 (ten) to a one byte representation.

Ah. That's easy:

int i = 10;
byte b = (byte)i;

Or just

byte b = 10;

--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too