strange behaviour when working with exceptions

[Chris]

Hi,

a strange behaviour when working with exceptions :

when I divide and integer by 0 will an exception be thrown. OK
but, when I divide a double by 0 is no exception thrown ???
How come ?

Try it out.

try
{
int i=1, j=0;
int result = i / j;

// double i=1.0, j=0;
// double result = i / j;

Console.WriteLine("Result {0} / {1} = {2}", i, j,result);
}
catch (Exception pExc)
{
Console.WriteLine("Exception caught : '{0}' ", pExc.Message);
}

can anybody explain this ?

thnx
Chris

[Stoitcho Goutsev \(100\) [C# MVP]]

Hi Chris,

So here what the docs say

"Dividing a floating-point value by zero will result in either positive
infinity, negative infinity, or Not-a-Number (NaN) according to the rules of
IEEE 754 arithmetic. Floating-point operations never throw an exception. For
more information, see Single and Double."

-and-

"If a floating-point operation is invalid, the result of the operation is
NaN."

Why? You probably can find the answer in IEEE specs.
--
HTH
Stoitcho Goutsev (100) [C# MVP]
"Chris" <ch********@pandora.be> wrote in message
news:uI***********************@phobos.telenet-ops.be...

Hi,

a strange behaviour when working with exceptions :

when I divide and integer by 0 will an exception be thrown. OK
but, when I divide a double by 0 is no exception thrown ???
How come ?

Try it out.

try
{
int i=1, j=0;
int result = i / j;

// double i=1.0, j=0;
// double result = i / j;

Console.WriteLine("Result {0} / {1} = {2}", i, j,result);
}
catch (Exception pExc)
{
Console.WriteLine("Exception caught : '{0}' ", pExc.Message);
}

can anybody explain this ?

thnx
Chris

[Nicholas Paldino [.NET/C# MVP]]

Chris,

This is right. The double type can represent infinity, positive or
negative, which is what you get when you divide by zero.

Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard.caspershouse.com

"Chris" <ch********@pandora.be> wrote in message
news:uI***********************@phobos.telenet-ops.be...

Hi,

a strange behaviour when working with exceptions :

when I divide and integer by 0 will an exception be thrown. OK
but, when I divide a double by 0 is no exception thrown ???
How come ?

Try it out.

try
{
int i=1, j=0;
int result = i / j;

// double i=1.0, j=0;
// double result = i / j;

Console.WriteLine("Result {0} / {1} = {2}", i, j,result);
}
catch (Exception pExc)
{
Console.WriteLine("Exception caught : '{0}' ", pExc.Message);
}

can anybody explain this ?

thnx
Chris