Setting a child form on top of another that has been activated

[Jose Egea]

Hello:
I have two child forms fChild1 and fChild2, and I want to set and reactivate
fChild2 over fChild1 when fChild1 is activated. I have tried with this code
in frmChild1, but it doesn't work, and now I dont't have any idea about how
to do it.
Can anybody help me, please?
Thanks in advance

private frmChild2 fChild2;
private void button1_Click(object sender, System.EventArgs e)
{
fChild2=new frmChild2();
fChild2.MdiParent=this.MdiParent ;
fChild2.Show();
}
private void frmChild1_Activated(object sender, System.EventArgs e)
{
if (!(fChild2==null))
{
fChild2.TopMost=true;
fChild2.BringToFront();
}
}

[Frans Bouma [C# MVP]]

Jose Egea wrote:

Hello:
I have two child forms fChild1 and fChild2, and I want to set and reactivate
fChild2 over fChild1 when fChild1 is activated. I have tried with this code
in frmChild1, but it doesn't work, and now I dont't have any idea about how
to do it.
Can anybody help me, please?
Thanks in advance

private frmChild2 fChild2;
private void button1_Click(object sender, System.EventArgs e)
{
fChild2=new frmChild2();
fChild2.MdiParent=this.MdiParent ;
fChild2.Show();
}
private void frmChild1_Activated(object sender, System.EventArgs e)
{
if (!(fChild2==null))
{
fChild2.TopMost=true;
fChild2.BringToFront();
}
}

MDI is a concept where there is no topmost or modal form. Any form visible
is part of a global UI which has to be accessable by the user. If you don't
want that, you shouldn't use MDI but SDI with for example dockable windows.

FB

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Microsoft C# MVP

[Morten Wennevik]

Hi Jose,

Instead of using TopMost, call Activate on fChild2;

Happy coding!
Morten Wennevik [C# MVP]