Xpath and arguments

[Jeppe BS]

got this method which works fine.

public string getNodeByName(string name)
{
XmlDocument personDB = new XmlDocument();
personDB.Load("persons.xml");

XmlNode root = personDB.DocumentElement;

XmlNodeList searchList = root.SelectNodes("//person[name='Casper']");

foreach (XmlNode node in searchList) {
output += node.OuterXml;
}
return output;
}

My problem is:
How can i pass a name to the XPath line ? instead of casper i wanne use
the name parameter ??

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[Nicholas Paldino [.NET/C# MVP]]

Jeppe,

I would use a simple string replacement, like this:

// Search the list.
XmlNodeList searchList = root.SelectNodes("//person[name='" + name + "']");

Or, if you want to be more efficient:

// Search the list.
XmlNodeList searchList =
root.SelectNodes(String.Format("//person[name='{0}']", name));

Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard.caspershouse.com
"Jeppe BS" <an*******@devdex.com> wrote in message
news:%2*****************@TK2MSFTNGP11.phx.gbl...

got this method which works fine.

public string getNodeByName(string name)
{
XmlDocument personDB = new XmlDocument();
personDB.Load("persons.xml");

XmlNode root = personDB.DocumentElement;

XmlNodeList searchList = root.SelectNodes("//person[name='Casper']");

foreach (XmlNode node in searchList) {
output += node.OuterXml;
}
return output;
}

My problem is:
How can i pass a name to the XPath line ? instead of casper i wanne use
the name parameter ??

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Don't just participate in USENET...get rewarded for it!

[Stefan]

Hi Jeppe
How about: XmlNodeList searchList = root.SelectNodes("//person[name='" +
parameter + "']"); ? ;-)
Greetings

"Jeppe BS" <an*******@devdex.com> wrote in message
news:%2*****************@TK2MSFTNGP11.phx.gbl...

got this method which works fine.

public string getNodeByName(string name)
{
XmlDocument personDB = new XmlDocument();
personDB.Load("persons.xml");

XmlNode root = personDB.DocumentElement;

XmlNodeList searchList = root.SelectNodes("//person[name='Casper']");

foreach (XmlNode node in searchList) {
output += node.OuterXml;
}
return output;
}

My problem is:
How can i pass a name to the XPath line ? instead of casper i wanne use
the name parameter ??

*** Sent via Developersdex http://www.developersdex.com ***
Don't just participate in USENET...get rewarded for it!