C# equality to Java >>> operator

[Dennis Myrén]

Hi.
Is there a C# operator that is equal to the java operator:

Regards
Dennis

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[Leon Lambert]

I think >>> was added to Java as a bit of a hack because they didn't
have any unsigned numbers. C# does support unsigned numbers like uint.
So if your intent is to shift right without extending sign bit. use uint
or ulong data types.

Hope this helps
Leon Lambert

Dennis Myrén wrote:

Hi.
Is there a C# operator that is equal to the java operator:
Regards
Dennis

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[Nicholas Paldino [.NET/C# MVP]]

Dennis,

From the java language specification, it says:

The value of n>>>s is n right-shifted s bit positions with zero-extension.
If n is positive, then the result is the same as that of n>>s; if n is
negative, the result is equal to that of the expression (n>>s)+(2<<~s) if
the type of the left-hand operand is int

So, if you have an integer in a variable n, you can do this:

// First, shift over two bits.
int pintResult = n >> s;

// Now, if it is negative, perform an additional operation.
if (pintResult < 0)
// Modify.
pintResult += (2 << ~s);

Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- ni**************@exisconsulting.com

"Dennis Myrén" <de**********@greydigital.no> wrote in message
news:Oh****************@TK2MSFTNGP10.phx.gbl...

Hi.
Is there a C# operator that is equal to the java operator:

Regards
Dennis

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