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treeView keydown

What is wrong in this code?

private void tree_KeyDown(ob ject sender, System.Windows. Forms.KeyEventA rgs
e)

{

if (e.KeyCode == Keys.Enter )

{

ConnString = "workstatio n id=HRV;packet size=4096;integ rated
security=SSPI;d ata source=HRV;pers ist security info=False;init ial
catalog=DVD Kolekcija";

bDb = new Db(ConnString);

grid.Refresh();
grid.Table = bDb.datasetDVD. Tables ["DVD"];

}

}

I press ENTER when I'm on treeview control but nothing happens!

Hrcko
Nov 17 '05 #1
8 4418
Hrvoje,

I would step through the code, and see if an exception is thrown
anywhere. If an exception is thrown, it will be swallowed by the code
calling your event handler, and do nothing.

Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard. caspershouse.co m

"Hrvoje Voda" <hr*********@lu atech.com> wrote in message
news:d1******** **@ls219.htnet. hr...
What is wrong in this code?

private void tree_KeyDown(ob ject sender, System.Windows. Forms.KeyEventA rgs
e)

{

if (e.KeyCode == Keys.Enter )

{

ConnString = "workstatio n id=HRV;packet size=4096;integ rated
security=SSPI;d ata source=HRV;pers ist security info=False;init ial
catalog=DVD Kolekcija";

bDb = new Db(ConnString);

grid.Refresh();
grid.Table = bDb.datasetDVD. Tables ["DVD"];

}

}

I press ENTER when I'm on treeview control but nothing happens!

Hrcko

Nov 17 '05 #2
Nothing is wrong with your code. Enter key is already used for an other
control (for example, if you set an accetButton for your form). The solution
is to says to the control that Enter key is an input key.

To do so, override TreeView class like following :
class TreeView2:TreeV iew {
protected override bool IsInputKey(Keys keyData) {
if (keyData==Keys. Enter) return true;
return base.IsInputKey (keyData);
}
}

Note that if you want to catch other keys like TAB, you can use a switch
statement. And if you want to catch ALL keys, always return true in
IsInputKey method.

And do not forget to replace
System.Windows. Form.TreeView tree;
par
TreeView2 tree;

et de même
tree=new System.Windows. Form.TreeView() ;
par
tree=new TreeView2();
Hope it helps,

Ludovic Soeur.

"Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
news:d1******** **@ls219.htnet. hr...
What is wrong in this code?

private void tree_KeyDown(ob ject sender, System.Windows. Forms.KeyEventA rgs
e)

{

if (e.KeyCode == Keys.Enter )

{

ConnString = "workstatio n id=HRV;packet size=4096;integ rated
security=SSPI;d ata source=HRV;pers ist security info=False;init ial
catalog=DVD Kolekcija";

bDb = new Db(ConnString);

grid.Refresh();
grid.Table = bDb.datasetDVD. Tables ["DVD"];

}

}

I press ENTER when I'm on treeview control but nothing happens!

Hrcko

Nov 17 '05 #3
I have a problem with overriding, because I'm using my user control.
I created some aditional functions for it, so when I put this code I can't
access my own functions!

Hrcko
"Ludovic SOEUR" <Lu***********@ hotmail.com> wrote in message
news:Ov******** ******@TK2MSFTN GP10.phx.gbl...
Nothing is wrong with your code. Enter key is already used for an other
control (for example, if you set an accetButton for your form). The
solution
is to says to the control that Enter key is an input key.

To do so, override TreeView class like following :
class TreeView2:TreeV iew {
protected override bool IsInputKey(Keys keyData) {
if (keyData==Keys. Enter) return true;
return base.IsInputKey (keyData);
}
}

Note that if you want to catch other keys like TAB, you can use a switch
statement. And if you want to catch ALL keys, always return true in
IsInputKey method.

And do not forget to replace
System.Windows. Form.TreeView tree;
par
TreeView2 tree;

et de même
tree=new System.Windows. Form.TreeView() ;
par
tree=new TreeView2();
Hope it helps,

Ludovic Soeur.

"Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
news:d1******** **@ls219.htnet. hr...
What is wrong in this code?

private void tree_KeyDown(ob ject sender,
System.Windows. Forms.KeyEventA rgs
e)

{

if (e.KeyCode == Keys.Enter )

{

ConnString = "workstatio n id=HRV;packet size=4096;integ rated
security=SSPI;d ata source=HRV;pers ist security info=False;init ial
catalog=DVD Kolekcija";

bDb = new Db(ConnString);

grid.Refresh();
grid.Table = bDb.datasetDVD. Tables ["DVD"];

}

}

I press ENTER when I'm on treeview control but nothing happens!

Hrcko


Nov 17 '05 #4
If I have understood, you have already overloaded TreeView, so just put
IsInputKey method in your overloaded control.
If I didn't, show me your code.

Ludovic Soeur.
"Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
news:d1******** **@ss405.t-com.hr...
I have a problem with overriding, because I'm using my user control.
I created some aditional functions for it, so when I put this code I can't
access my own functions!

Hrcko
"Ludovic SOEUR" <Lu***********@ hotmail.com> wrote in message
news:Ov******** ******@TK2MSFTN GP10.phx.gbl...
Nothing is wrong with your code. Enter key is already used for an other
control (for example, if you set an accetButton for your form). The
solution
is to says to the control that Enter key is an input key.

To do so, override TreeView class like following :
class TreeView2:TreeV iew {
protected override bool IsInputKey(Keys keyData) {
if (keyData==Keys. Enter) return true;
return base.IsInputKey (keyData);
}
}

Note that if you want to catch other keys like TAB, you can use a switch
statement. And if you want to catch ALL keys, always return true in
IsInputKey method.

And do not forget to replace
System.Windows. Form.TreeView tree;
par
TreeView2 tree;

et de même
tree=new System.Windows. Form.TreeView() ;
par
tree=new TreeView2();
Hope it helps,

Ludovic Soeur.

"Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
news:d1******** **@ls219.htnet. hr...
What is wrong in this code?

private void tree_KeyDown(ob ject sender,
System.Windows. Forms.KeyEventA rgs
e)

{

if (e.KeyCode == Keys.Enter )

{

ConnString = "workstatio n id=HRV;packet size=4096;integ rated
security=SSPI;d ata source=HRV;pers ist security info=False;init ial
catalog=DVD Kolekcija";

bDb = new Db(ConnString);

grid.Refresh();
grid.Table = bDb.datasetDVD. Tables ["DVD"];

}

}

I press ENTER when I'm on treeview control but nothing happens!

Hrcko



Nov 17 '05 #5
I put IsInputKey method in my user control, but it still doesn't work!
Should I call it somehow in my other application?

Hrcko
"Ludovic SOEUR" <Lu***********@ hotmail.com> wrote in message
news:%2******** ********@TK2MSF TNGP14.phx.gbl. ..
If I have understood, you have already overloaded TreeView, so just put
IsInputKey method in your overloaded control.
If I didn't, show me your code.

Ludovic Soeur.
"Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
news:d1******** **@ss405.t-com.hr...
I have a problem with overriding, because I'm using my user control.
I created some aditional functions for it, so when I put this code I
can't
access my own functions!

Hrcko
"Ludovic SOEUR" <Lu***********@ hotmail.com> wrote in message
news:Ov******** ******@TK2MSFTN GP10.phx.gbl...
> Nothing is wrong with your code. Enter key is already used for an other
> control (for example, if you set an accetButton for your form). The
> solution
> is to says to the control that Enter key is an input key.
>
> To do so, override TreeView class like following :
> class TreeView2:TreeV iew {
> protected override bool IsInputKey(Keys keyData) {
> if (keyData==Keys. Enter) return true;
> return base.IsInputKey (keyData);
> }
> }
>
> Note that if you want to catch other keys like TAB, you can use a
> switch
> statement. And if you want to catch ALL keys, always return true in
> IsInputKey method.
>
> And do not forget to replace
> System.Windows. Form.TreeView tree;
> par
> TreeView2 tree;
>
> et de même
> tree=new System.Windows. Form.TreeView() ;
> par
> tree=new TreeView2();
>
>
> Hope it helps,
>
> Ludovic Soeur.
>
> "Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
> news:d1******** **@ls219.htnet. hr...
>> What is wrong in this code?
>>
>> private void tree_KeyDown(ob ject sender,
>> System.Windows. Forms.KeyEventA rgs
>> e)
>>
>> {
>>
>> if (e.KeyCode == Keys.Enter )
>>
>> {
>>
>> ConnString = "workstatio n id=HRV;packet size=4096;integ rated
>> security=SSPI;d ata source=HRV;pers ist security info=False;init ial
>> catalog=DVD Kolekcija";
>>
>> bDb = new Db(ConnString);
>>
>> grid.Refresh();
>>
>>
>> grid.Table = bDb.datasetDVD. Tables ["DVD"];
>>
>> }
>>
>> }
>>
>>
>>
>> I press ENTER when I'm on treeview control but nothing happens!
>>
>>
>>
>> Hrcko
>>
>>
>
>



Nov 17 '05 #6
Show me your code...

"Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
news:d1******** **@ss405.t-com.hr...
I put IsInputKey method in my user control, but it still doesn't work!
Should I call it somehow in my other application?

Hrcko
"Ludovic SOEUR" <Lu***********@ hotmail.com> wrote in message
news:%2******** ********@TK2MSF TNGP14.phx.gbl. ..
If I have understood, you have already overloaded TreeView, so just put
IsInputKey method in your overloaded control.
If I didn't, show me your code.

Ludovic Soeur.
"Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
news:d1******** **@ss405.t-com.hr...
I have a problem with overriding, because I'm using my user control.
I created some aditional functions for it, so when I put this code I
can't
access my own functions!

Hrcko
"Ludovic SOEUR" <Lu***********@ hotmail.com> wrote in message
news:Ov******** ******@TK2MSFTN GP10.phx.gbl...
> Nothing is wrong with your code. Enter key is already used for an other > control (for example, if you set an accetButton for your form). The
> solution
> is to says to the control that Enter key is an input key.
>
> To do so, override TreeView class like following :
> class TreeView2:TreeV iew {
> protected override bool IsInputKey(Keys keyData) {
> if (keyData==Keys. Enter) return true;
> return base.IsInputKey (keyData);
> }
> }
>
> Note that if you want to catch other keys like TAB, you can use a
> switch
> statement. And if you want to catch ALL keys, always return true in
> IsInputKey method.
>
> And do not forget to replace
> System.Windows. Form.TreeView tree;
> par
> TreeView2 tree;
>
> et de même
> tree=new System.Windows. Form.TreeView() ;
> par
> tree=new TreeView2();
>
>
> Hope it helps,
>
> Ludovic Soeur.
>
> "Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
> news:d1******** **@ls219.htnet. hr...
>> What is wrong in this code?
>>
>> private void tree_KeyDown(ob ject sender,
>> System.Windows. Forms.KeyEventA rgs
>> e)
>>
>> {
>>
>> if (e.KeyCode == Keys.Enter )
>>
>> {
>>
>> ConnString = "workstatio n id=HRV;packet size=4096;integ rated
>> security=SSPI;d ata source=HRV;pers ist security info=False;init ial
>> catalog=DVD Kolekcija";
>>
>> bDb = new Db(ConnString);
>>
>> grid.Refresh();
>>
>>
>> grid.Table = bDb.datasetDVD. Tables ["DVD"];
>>
>> }
>>
>> }
>>
>>
>>
>> I press ENTER when I'm on treeview control but nothing happens!
>>
>>
>>
>> Hrcko
>>
>>
>
>



Nov 17 '05 #7
In my application I have my user control and this code :

in constructor :

treeKolekcija.K eyDown += new KeyEventHandler (tree_KeyDown) ;

private void tree_KeyDown(ob ject sender, System.Windows. Forms.KeyEventA rgs
e)
{
if (e.KeyCode == Keys.Enter )
{
ConnString = "workstatio n id=HRV;packet size=4096;integ rated
security=SSPI;d ata source=HRV;pers ist security info=False;init ial
catalog=DVD Kolekcija";
bDb = new Db(ConnString);
grid.Refresh();
grid.Table = bDb.datasetDVD. Tables ["DVD"];
}
}

I put your code into my user control :

protected override bool IsInputKey(Keys keyData)
{
if (keyData==Keys. Enter) return true;
return base.IsInputKey (keyData);
}

"Ludovic SOEUR" <Lu***********@ hotmail.com> wrote in message
news:Oi******** ******@tk2msftn gp13.phx.gbl...
Show me your code...

"Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
news:d1******** **@ss405.t-com.hr...
I put IsInputKey method in my user control, but it still doesn't work!
Should I call it somehow in my other application?

Hrcko
"Ludovic SOEUR" <Lu***********@ hotmail.com> wrote in message
news:%2******** ********@TK2MSF TNGP14.phx.gbl. ..
> If I have understood, you have already overloaded TreeView, so just put
> IsInputKey method in your overloaded control.
> If I didn't, show me your code.
>
> Ludovic Soeur.
>
>
> "Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
> news:d1******** **@ss405.t-com.hr...
>> I have a problem with overriding, because I'm using my user control.
>> I created some aditional functions for it, so when I put this code I
>> can't
>> access my own functions!
>>
>> Hrcko
>>
>>
>> "Ludovic SOEUR" <Lu***********@ hotmail.com> wrote in message
>> news:Ov******** ******@TK2MSFTN GP10.phx.gbl...
>> > Nothing is wrong with your code. Enter key is already used for an other >> > control (for example, if you set an accetButton for your form). The
>> > solution
>> > is to says to the control that Enter key is an input key.
>> >
>> > To do so, override TreeView class like following :
>> > class TreeView2:TreeV iew {
>> > protected override bool IsInputKey(Keys keyData) {
>> > if (keyData==Keys. Enter) return true;
>> > return base.IsInputKey (keyData);
>> > }
>> > }
>> >
>> > Note that if you want to catch other keys like TAB, you can use a
>> > switch
>> > statement. And if you want to catch ALL keys, always return true in
>> > IsInputKey method.
>> >
>> > And do not forget to replace
>> > System.Windows. Form.TreeView tree;
>> > par
>> > TreeView2 tree;
>> >
>> > et de même
>> > tree=new System.Windows. Form.TreeView() ;
>> > par
>> > tree=new TreeView2();
>> >
>> >
>> > Hope it helps,
>> >
>> > Ludovic Soeur.
>> >
>> > "Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
>> > news:d1******** **@ls219.htnet. hr...
>> >> What is wrong in this code?
>> >>
>> >> private void tree_KeyDown(ob ject sender,
>> >> System.Windows. Forms.KeyEventA rgs
>> >> e)
>> >>
>> >> {
>> >>
>> >> if (e.KeyCode == Keys.Enter )
>> >>
>> >> {
>> >>
>> >> ConnString = "workstatio n id=HRV;packet size=4096;integ rated
>> >> security=SSPI;d ata source=HRV;pers ist security info=False;init ial
>> >> catalog=DVD Kolekcija";
>> >>
>> >> bDb = new Db(ConnString);
>> >>
>> >> grid.Refresh();
>> >>
>> >>
>> >> grid.Table = bDb.datasetDVD. Tables ["DVD"];
>> >>
>> >> }
>> >>
>> >> }
>> >>
>> >>
>> >>
>> >> I press ENTER when I'm on treeview control but nothing happens!
>> >>
>> >>
>> >>
>> >> Hrcko
>> >>
>> >>
>> >
>> >
>>
>>
>
>



Nov 17 '05 #8
This is how you must change your code :

namespace MonNameSpace {
public class MyUserControl : UserControl {
....
....
TreeView2 treeKolekcija;
....
....
....
private void InitializeCompo nent() {
...
...
this.treeKolekc ija = new TreeView2();
...
...
}
...
...
private void tree_KeyDown(ob ject sender,
System.Windows. Forms.KeyEventA rgs e) {
...
your code
...
}
...
...
}
class TreeView2:TreeV iew {
protected override bool IsInputKey(Keys keyData) {
if (keyData==Keys. Enter) return true;
return base.IsInputKey (keyData);
}
}
}

Of course, if you have already overloaded TreeView Class, do not extend
TreeView2 from TreeView but from your own TreeView class.

Hope it helps...
If it does not, I would send you a complete example.

Ludovic Soeur.

"Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
news:d2******** **@ss405.t-com.hr...
In my application I have my user control and this code :

in constructor :

treeKolekcija.K eyDown += new KeyEventHandler (tree_KeyDown) ;

private void tree_KeyDown(ob ject sender, System.Windows. Forms.KeyEventA rgs e)
{
if (e.KeyCode == Keys.Enter )
{
ConnString = "workstatio n id=HRV;packet size=4096;integ rated
security=SSPI;d ata source=HRV;pers ist security info=False;init ial
catalog=DVD Kolekcija";
bDb = new Db(ConnString);
grid.Refresh();
grid.Table = bDb.datasetDVD. Tables ["DVD"];
}
}

I put your code into my user control :

protected override bool IsInputKey(Keys keyData)
{
if (keyData==Keys. Enter) return true;
return base.IsInputKey (keyData);
}

"Ludovic SOEUR" <Lu***********@ hotmail.com> wrote in message
news:Oi******** ******@tk2msftn gp13.phx.gbl...
Show me your code...

"Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
news:d1******** **@ss405.t-com.hr...
I put IsInputKey method in my user control, but it still doesn't work!
Should I call it somehow in my other application?

Hrcko
"Ludovic SOEUR" <Lu***********@ hotmail.com> wrote in message
news:%2******** ********@TK2MSF TNGP14.phx.gbl. ..
> If I have understood, you have already overloaded TreeView, so just put > IsInputKey method in your overloaded control.
> If I didn't, show me your code.
>
> Ludovic Soeur.
>
>
> "Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
> news:d1******** **@ss405.t-com.hr...
>> I have a problem with overriding, because I'm using my user control.
>> I created some aditional functions for it, so when I put this code I
>> can't
>> access my own functions!
>>
>> Hrcko
>>
>>
>> "Ludovic SOEUR" <Lu***********@ hotmail.com> wrote in message
>> news:Ov******** ******@TK2MSFTN GP10.phx.gbl...
>> > Nothing is wrong with your code. Enter key is already used for an

other
>> > control (for example, if you set an accetButton for your form). The >> > solution
>> > is to says to the control that Enter key is an input key.
>> >
>> > To do so, override TreeView class like following :
>> > class TreeView2:TreeV iew {
>> > protected override bool IsInputKey(Keys keyData) {
>> > if (keyData==Keys. Enter) return true;
>> > return base.IsInputKey (keyData);
>> > }
>> > }
>> >
>> > Note that if you want to catch other keys like TAB, you can use a
>> > switch
>> > statement. And if you want to catch ALL keys, always return true in >> > IsInputKey method.
>> >
>> > And do not forget to replace
>> > System.Windows. Form.TreeView tree;
>> > par
>> > TreeView2 tree;
>> >
>> > et de même
>> > tree=new System.Windows. Form.TreeView() ;
>> > par
>> > tree=new TreeView2();
>> >
>> >
>> > Hope it helps,
>> >
>> > Ludovic Soeur.
>> >
>> > "Hrvoje Voda" <hr*********@lu atech.com> a écrit dans le message de
>> > news:d1******** **@ls219.htnet. hr...
>> >> What is wrong in this code?
>> >>
>> >> private void tree_KeyDown(ob ject sender,
>> >> System.Windows. Forms.KeyEventA rgs
>> >> e)
>> >>
>> >> {
>> >>
>> >> if (e.KeyCode == Keys.Enter )
>> >>
>> >> {
>> >>
>> >> ConnString = "workstatio n id=HRV;packet size=4096;integ rated
>> >> security=SSPI;d ata source=HRV;pers ist security info=False;init ial
>> >> catalog=DVD Kolekcija";
>> >>
>> >> bDb = new Db(ConnString);
>> >>
>> >> grid.Refresh();
>> >>
>> >>
>> >> grid.Table = bDb.datasetDVD. Tables ["DVD"];
>> >>
>> >> }
>> >>
>> >> }
>> >>
>> >>
>> >>
>> >> I press ENTER when I'm on treeview control but nothing happens!
>> >>
>> >>
>> >>
>> >> Hrcko
>> >>
>> >>
>> >
>> >
>>
>>
>
>



Nov 17 '05 #9

This thread has been closed and replies have been disabled. Please start a new discussion.

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marktang
by: marktang | last post by:
ONU (Optical Network Unit) is one of the key components for providing high-speed Internet services. Its primary function is to act as an endpoint device located at the user's premises. However, people are often confused as to whether an ONU can Work As a Router. In this blog post, we’ll explore What is ONU, What Is Router, ONU & Router’s main usage, and What is the difference between ONU and Router. Let’s take a closer look ! Part I. Meaning of...
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by: Hystou | last post by:
Most computers default to English, but sometimes we require a different language, especially when relocating. Forgot to request a specific language before your computer shipped? No problem! You can effortlessly switch the default language on Windows 10 without reinstalling. I'll walk you through it. First, let's disable language synchronization. With a Microsoft account, language settings sync across devices. To prevent any complications,...
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Oralloy
by: Oralloy | last post by:
Hello folks, I am unable to find appropriate documentation on the type promotion of bit-fields when using the generalised comparison operator "<=>". The problem is that using the GNU compilers, it seems that the internal comparison operator "<=>" tries to promote arguments from unsigned to signed. This is as boiled down as I can make it. Here is my compilation command: g++-12 -std=c++20 -Wnarrowing bit_field.cpp Here is the code in...
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jinu1996
by: jinu1996 | last post by:
In today's digital age, having a compelling online presence is paramount for businesses aiming to thrive in a competitive landscape. At the heart of this digital strategy lies an intricately woven tapestry of website design and digital marketing. It's not merely about having a website; it's about crafting an immersive digital experience that captivates audiences and drives business growth. The Art of Business Website Design Your website is...
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isladogs
by: isladogs | last post by:
The next Access Europe User Group meeting will be on Wednesday 1 May 2024 starting at 18:00 UK time (6PM UTC+1) and finishing by 19:30 (7.30PM). In this session, we are pleased to welcome a new presenter, Adolph Dupré who will be discussing some powerful techniques for using class modules. He will explain when you may want to use classes instead of User Defined Types (UDT). For example, to manage the data in unbound forms. Adolph will...
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by: TSSRALBI | last post by:
Hello I'm a network technician in training and I need your help. I am currently learning how to create and manage the different types of VPNs and I have a question about LAN-to-LAN VPNs. The last exercise I practiced was to create a LAN-to-LAN VPN between two Pfsense firewalls, by using IPSEC protocols. I succeeded, with both firewalls in the same network. But I'm wondering if it's possible to do the same thing, with 2 Pfsense firewalls...
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by: adsilva | last post by:
A Windows Forms form does not have the event Unload, like VB6. What one acts like?
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muto222
by: muto222 | last post by:
How can i add a mobile payment intergratation into php mysql website.
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bsmnconsultancy
by: bsmnconsultancy | last post by:
In today's digital era, a well-designed website is crucial for businesses looking to succeed. Whether you're a small business owner or a large corporation in Toronto, having a strong online presence can significantly impact your brand's success. BSMN Consultancy, a leader in Website Development in Toronto offers valuable insights into creating effective websites that not only look great but also perform exceptionally well. In this comprehensive...

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