Display an hyperlink column in gridview using TemplateField

[Valli]

Hi,

I need to display an hyperlink column in gridview where if the user
clicks that column the page should move to the selected page.
I have got help from this group & started using template field. After using
this, I couldnt see a column supporting hyperlink.
In the gridviews first column header, there appears an hyperlink with the
first record link displaying. That also only in header overwriting with the
first column caption.

can anyone help me in this..

My code follows here...

<asp:TemplateField>
<ItemTemplate>

<asp:HyperLink ID="HyperLink2" runat="server" NavigateUrl='<%#
Eval("FileLink") %>'

Style="z-index: 100; left: 0px; position: absolute; top: 0px" Text='<%#
Eval("FileLink") %>'></asp:HyperLink>

</ItemTemplate>
</asp:TemplateField>

--FileLink is the datafield name which provides the link
--
Thanks & Regards
Valli

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<asp:XmlDataSource ID="XmlDataSource1" runat="server">
<Data>
<Links>
<Link FileLink="http://www.microsoft.com"/>
<Link FileLink="http://msdn.microsoft.com"/>
<Link FileLink="http://technet.microsoft.com"/>
</Links>
</Data>
</asp:XmlDataSource>

is the source for

<asp:GridView ID="GridView1" runat="server" DataSourceID="XmlDataSource1">
<Columns>
<asp:HyperLinkField
DataNavigateUrlFields="FileLink"
DataTextField="FileLink"/>
</Columns>
</asp:GridView>

and

<asp:GridView ID="GridView2" runat="server" DataSourceID="XmlDataSource1">
<Columns>
<asp:TemplateField>
<ItemTemplate>
<asp:HyperLink ID="HyperLink1" runat="server"
Text='<%# Eval("FileLink") %>'
NavigateUrl='<%# Eval("FileLink") %>'>
</asp:HyperLink>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>

We could help you, and others, better if you post more of your code rather
than just posting a TemplateField. At least then when someone copies and
pastes the code into a new ASPX page it'll produce a result.