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REGEX. What am I doing wrong?

Hello,

I need to create a REGEX which accepts only phone numbers.

The phone numbers start allways with 261, 21, 96 or 91 and have 7
numbers after it.

Something like. 261 1223346, 21 2334456, etc.

I tried the following but it is not working:
^(?:261|21|96|91)\s\d{7}$

How can I do this?

Thanks,

Miguel

Feb 26 '07 #1
11 1129
On Feb 26, 2:11 pm, "shapper" <mdmo...@gmail.comwrote:
Hello,

I need to create a REGEX which accepts only phone numbers.

The phone numbers start allways with 261, 21, 96 or 91 and have 7
numbers after it.

Something like. 261 1223346, 21 2334456, etc.

I tried the following but it is not working:
^(?:261|21|96|91)\s\d{7}$
if (?:) means a noncapturing group then you need a parenthesis

^?:(261|21|96|91)\s\d{7}$

Feb 26 '07 #2
Hi there again,

I believe it should work. I'm note sure how you utilized this regular
expression but if you're trying validate user input via regular expression
validation control
ValidationExpression="^(261|21|96|91)\s*\d{7}$"
should be enough. Otherwise, if you try to validate and get both area code
this might be an idea how to do that:

string pattern = @"^(261|21|96|91)\s(\d{7})$";

System.Text.RegularExpressions.Match match =
System.Text.RegularExpressions.Regex.Match(
txtPhone.Text, pattern);

if (match.Success)
{
string areaCode = match.Groups[1].Value;
string number = match.Groups[2].Value;
}
else
{
// not valid
}
--

Hope this helps

Milosz
"shapper" wrote:
Hello,

I need to create a REGEX which accepts only phone numbers.

The phone numbers start allways with 261, 21, 96 or 91 and have 7
numbers after it.

Something like. 261 1223346, 21 2334456, etc.

I tried the following but it is not working:
^(?:261|21|96|91)\s\d{7}$

How can I do this?

Thanks,

Miguel

Feb 26 '07 #3
^((261)|(21)|(96)|(91))\s\d{7}$

works for me
Peter

"shapper" <md*****@gmail.comwrote in message
news:11**********************@m58g2000cwm.googlegr oups.com...
Hello,

I need to create a REGEX which accepts only phone numbers.

The phone numbers start allways with 261, 21, 96 or 91 and have 7
numbers after it.

Something like. 261 1223346, 21 2334456, etc.

I tried the following but it is not working:
^(?:261|21|96|91)\s\d{7}$

How can I do this?

Thanks,

Miguel

Feb 26 '07 #4
On Feb 26, 2:44 pm, "Peter Bradley" <pbrad...@uwic.ac.ukwrote:
^((261)|(21)|(96)|(91))\s\d{7}$

works for me

Peter

"shapper" <mdmo...@gmail.comwrote in message

news:11**********************@m58g2000cwm.googlegr oups.com...
Hello,
I need to create a REGEX which accepts only phone numbers.
The phone numbers start allways with 261, 21, 96 or 91 and have 7
numbers after it.
Something like. 261 1223346, 21 2334456, etc.
I tried the following but it is not working:
^(?:261|21|96|91)\s\d{7}$
How can I do this?
Thanks,
Miguel- Hide quoted text -

- Show quoted text -
http://groups.google.com/group/micro...fc7a34ed155ad8

Feb 26 '07 #5
On Feb 26, 1:44 pm, "Peter Bradley" <pbrad...@uwic.ac.ukwrote:
^((261)|(21)|(96)|(91))\s\d{7}$

works for me

Peter

"shapper" <mdmo...@gmail.comwrote in message

news:11**********************@m58g2000cwm.googlegr oups.com...
Hello,
I need to create a REGEX which accepts only phone numbers.
The phone numbers start allways with 261, 21, 96 or 91 and have 7
numbers after it.
Something like. 261 1223346, 21 2334456, etc.
I tried the following but it is not working:
^(?:261|21|96|91)\s\d{7}$
How can I do this?
Thanks,
Miguel
Hi,

It really does not work. Please try:

' Create new regex
Dim regex As System.Text.RegularExpressions.Regex
regex = New RegularExpressions.Regex("^((261)|(21)|(96)|(91))\ s
\d{7}$")

' Check if expression is a match
Response.Write(regex.IsMatch("961234567").ToString )

It returns False.

Any idea?

Thanks,
Miguel

Feb 26 '07 #6
On Feb 26, 1:49 pm, "Alexey Smirnov" <alexey.smir...@gmail.comwrote:
On Feb 26, 2:44 pm, "Peter Bradley" <pbrad...@uwic.ac.ukwrote:
^((261)|(21)|(96)|(91))\s\d{7}$
works for me
Peter
"shapper" <mdmo...@gmail.comwrote in message
news:11**********************@m58g2000cwm.googlegr oups.com...
Hello,
I need to create a REGEX which accepts only phone numbers.
The phone numbers start allways with 261, 21, 96 or 91 and have 7
numbers after it.
Something like. 261 1223346, 21 2334456, etc.
I tried the following but it is not working:
^(?:261|21|96|91)\s\d{7}$
How can I do this?
Thanks,
Miguel- Hide quoted text -
- Show quoted text -

http://groups.google.com/group/micro...framework.aspn...
Hi Alexey,

I also tried your suggestion and a few others and it does not work.
Any idea?

Thanks,
Miguel

Feb 26 '07 #7
On Feb 26, 3:32 pm, "shapper" <mdmo...@gmail.comwrote:
On Feb 26, 1:49 pm, "Alexey Smirnov" <alexey.smir...@gmail.comwrote:


On Feb 26, 2:44 pm, "Peter Bradley" <pbrad...@uwic.ac.ukwrote:
^((261)|(21)|(96)|(91))\s\d{7}$
works for me
Peter
"shapper" <mdmo...@gmail.comwrote in message
>news:11**********************@m58g2000cwm.googleg roups.com...
Hello,
I need to create a REGEX which accepts only phone numbers.
The phone numbers start allways with 261, 21, 96 or 91 and have 7
numbers after it.
Something like. 261 1223346, 21 2334456, etc.
I tried the following but it is not working:
^(?:261|21|96|91)\s\d{7}$
How can I do this?
Thanks,
Miguel- Hide quoted text -
- Show quoted text -
http://groups.google.com/group/micro...framework.aspn...

Hi Alexey,

I also tried your suggestion and a few others and it does not work.
because of \s what mean a single space

regex = New RegularExpressions.Regex("^((261)|(21)|(96)|(91))\ d{7}$")

Feb 26 '07 #8
The examples the OP gave were (I copy and paste):

261 1223346, 21 2334456

I assume that means a space is needed between the prefix and the last 7
digits.

So it still works for me on that basis.
Peter
Hi,

It really does not work. Please try:

' Create new regex
Dim regex As System.Text.RegularExpressions.Regex
regex = New RegularExpressions.Regex("^((261)|(21)|(96)|(91))\ s
\d{7}$")

' Check if expression is a match
Response.Write(regex.IsMatch("961234567").ToString )

It returns False.

Any idea?

Thanks,
Miguel

Feb 26 '07 #9
You should have told us space is optional:

string pattern = @"^(261|21|96|91)\s*\d{7}$";

should do the job.
--
Milosz
"shapper" wrote:
On Feb 26, 1:44 pm, "Peter Bradley" <pbrad...@uwic.ac.ukwrote:
^((261)|(21)|(96)|(91))\s\d{7}$

works for me

Peter

"shapper" <mdmo...@gmail.comwrote in message

news:11**********************@m58g2000cwm.googlegr oups.com...
Hello,
I need to create a REGEX which accepts only phone numbers.
The phone numbers start allways with 261, 21, 96 or 91 and have 7
numbers after it.
Something like. 261 1223346, 21 2334456, etc.
I tried the following but it is not working:
^(?:261|21|96|91)\s\d{7}$
How can I do this?
Thanks,
Miguel

Hi,

It really does not work. Please try:

' Create new regex
Dim regex As System.Text.RegularExpressions.Regex
regex = New RegularExpressions.Regex("^((261)|(21)|(96)|(91))\ s
\d{7}$")

' Check if expression is a match
Response.Write(regex.IsMatch("961234567").ToString )

It returns False.

Any idea?

Thanks,
Miguel

Feb 26 '07 #10
Yep. Good specs. So hard to come by.

:)
Peter

"Milosz Skalecki [MCAD]" <mi*****@DONTLIKESPAMwp.plwrote in message
news:56**********************************@microsof t.com...
You should have told us space is optional:

string pattern = @"^(261|21|96|91)\s*\d{7}$";

should do the job.
--
Milosz
"shapper" wrote:
>On Feb 26, 1:44 pm, "Peter Bradley" <pbrad...@uwic.ac.ukwrote:
^((261)|(21)|(96)|(91))\s\d{7}$

works for me

Peter

"shapper" <mdmo...@gmail.comwrote in message

news:11**********************@m58g2000cwm.googlegr oups.com...

Hello,

I need to create a REGEX which accepts only phone numbers.

The phone numbers start allways with 261, 21, 96 or 91 and have 7
numbers after it.

Something like. 261 1223346, 21 2334456, etc.

I tried the following but it is not working:
^(?:261|21|96|91)\s\d{7}$

How can I do this?

Thanks,

Miguel

Hi,

It really does not work. Please try:

' Create new regex
Dim regex As System.Text.RegularExpressions.Regex
regex = New RegularExpressions.Regex("^((261)|(21)|(96)|(91))\ s
\d{7}$")

' Check if expression is a match
Response.Write(regex.IsMatch("961234567").ToString )

It returns False.

Any idea?

Thanks,
Miguel


Feb 27 '07 #11
On Feb 27, 7:41 am, "Peter Bradley" <pbrad...@uwic.ac.ukwrote:
Yep. Good specs. So hard to come by.

:)

Peter

"Milosz Skalecki [MCAD]" <mily...@DONTLIKESPAMwp.plwrote in messagenews:56**********************************@m icrosoft.com...
You should have told us space is optional:
string pattern = @"^(261|21|96|91)\s*\d{7}$";
should do the job.
--
Milosz
"shapper" wrote:
On Feb 26, 1:44 pm, "Peter Bradley" <pbrad...@uwic.ac.ukwrote:
^((261)|(21)|(96)|(91))\s\d{7}$
works for me
Peter
"shapper" <mdmo...@gmail.comwrote in message
news:11**********************@m58g2000cwm.googlegr oups.com...
Hello,
I need to create a REGEX which accepts only phone numbers.
The phone numbers start allways with 261, 21, 96 or 91 and have 7
numbers after it.
Something like. 261 1223346, 21 2334456, etc.
I tried the following but it is not working:
^(?:261|21|96|91)\s\d{7}$
How can I do this?
Thanks,
Miguel
Hi,
It really does not work. Please try:
' Create new regex
Dim regex As System.Text.RegularExpressions.Regex
regex = New RegularExpressions.Regex("^((261)|(21)|(96)|(91))\ s
\d{7}$")
' Check if expression is a match
Response.Write(regex.IsMatch("961234567").ToString )
It returns False.
Any idea?
Thanks,
Miguel
Thank You All.

It is working fine now.

Thanks,
Miguel

Feb 27 '07 #12

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