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Showfooter not working?

Hi

I would like to insert a new row in this gridview but the showfooter=true is
not working?

thanks

N

<%@ Page Language="VB" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"

"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<script runat="server">

Public Class person

Dim _name As String

Public Property Name()

Get

Return _name

End Get

Set(ByVal value)

_name = value

End Set

End Property



End Class

Public Class PersonCollection : Inherits CollectionBase

Sub New()

MyBase.New()

End Sub

Public Property item(ByVal i As Integer)

Get

Return Me.List(i)

End Get

Set(ByVal value)

Me.List(i) = value

End Set

End Property

Public Sub add(ByVal item As person)

Me.List.Add(item)

End Sub

End Class

Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles
Me.Load

If Not IsPostBack Then

GridView2.DataSource = source()

GridView2.DataBind()

End If

End Sub

Protected Function source() As PersonCollection

Dim objPersonCollection As New PersonCollection

For a As Integer = 0 To 3

Dim objPerson As New person

objPerson.Name = "Name" + a.ToString

objPersonCollection.add(objPerson)

Next

Return objPersonCollection

End Function

Protected Sub Button1_Click(ByVal sender As Object, ByVal e As
System.EventArgs)

GridView2.ShowFooter = True

End Sub

</script>

<html xmlns="http://www.w3.org/1999/xhtml">

<head id="Head1" runat="server">

<title></title>

</head>

<body>

<form id="form1" runat="server">

<div>

<asp:GridView ID="GridView2" runat="server" AutoGenerateColumns="False">

<Columns>

<asp:TemplateField>

<ItemTemplate>

<asp:TextBox ID="tb" runat="server" Text="<%#Bind('name') %>"></asp:TextBox>

</ItemTemplate>

<FooterTemplate>

<asp:TextBox ID="tb2" runat="server"></asp:TextBox>

</FooterTemplate>

</asp:TemplateField>

</Columns>

</asp:GridView>

<asp:Button ID="Button1" runat="server" OnClick="Button1_Click"
Text="Button" />

</div>

</form>

</body>

</html>
Feb 2 '07 #1
1 5138
Hi Nick,

Because footer is rendered on databinding, there is no way you can make it
visble afterwards. You have to rebind the data:

Protected Sub Button1_Click(ByVal sender As Object, ByVal e As
System.EventArgs)

GridView2.ShowFooter = True
GridView2.DataSource = source()
GridView2.DataBind()

End Sub
--
Milosz
"Nick C" wrote:
Hi

I would like to insert a new row in this gridview but the showfooter=true is
not working?

thanks

N

<%@ Page Language="VB" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"

"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<script runat="server">

Public Class person

Dim _name As String

Public Property Name()

Get

Return _name

End Get

Set(ByVal value)

_name = value

End Set

End Property



End Class

Public Class PersonCollection : Inherits CollectionBase

Sub New()

MyBase.New()

End Sub

Public Property item(ByVal i As Integer)

Get

Return Me.List(i)

End Get

Set(ByVal value)

Me.List(i) = value

End Set

End Property

Public Sub add(ByVal item As person)

Me.List.Add(item)

End Sub

End Class

Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles
Me.Load

If Not IsPostBack Then

GridView2.DataSource = source()

GridView2.DataBind()

End If

End Sub

Protected Function source() As PersonCollection

Dim objPersonCollection As New PersonCollection

For a As Integer = 0 To 3

Dim objPerson As New person

objPerson.Name = "Name" + a.ToString

objPersonCollection.add(objPerson)

Next

Return objPersonCollection

End Function

Protected Sub Button1_Click(ByVal sender As Object, ByVal e As
System.EventArgs)

GridView2.ShowFooter = True

End Sub

</script>

<html xmlns="http://www.w3.org/1999/xhtml">

<head id="Head1" runat="server">

<title></title>

</head>

<body>

<form id="form1" runat="server">

<div>

<asp:GridView ID="GridView2" runat="server" AutoGenerateColumns="False">

<Columns>

<asp:TemplateField>

<ItemTemplate>

<asp:TextBox ID="tb" runat="server" Text="<%#Bind('name') %>"></asp:TextBox>

</ItemTemplate>

<FooterTemplate>

<asp:TextBox ID="tb2" runat="server"></asp:TextBox>

</FooterTemplate>

</asp:TemplateField>

</Columns>

</asp:GridView>

<asp:Button ID="Button1" runat="server" OnClick="Button1_Click"
Text="Button" />

</div>

</form>

</body>

</html>
Feb 2 '07 #2

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