Length of digit after decimal point

[Stefantastisk]

Hey there,

Anyone knows a clever method for knowing the length of the digit after
a decimal point in a standard C# decimal value, WITHOUT use of any
string formatting.

Example:
5231,12231 <- Lengt = 5

Tnx for your attention hope you are capable of helping.

Kind regards
Stefan

[John Timney \(MVP\)]

You could just split it apart, without any formatting

Double start_value = 5231.12231;
string[] end_values = start_value.ToString().Split('.');
int slen = end_values[1].Length;
Response.Write(slen);

--
Regards

John Timney (MVP)
VISIT MY WEBSITE:
http://www.johntimney.com
http://www.johntimney.com/blog
"Stefantastisk" <st***********@gmail.comwrote in message
news:11**********************@b28g2000cwb.googlegr oups.com...

Hey there,

Anyone knows a clever method for knowing the length of the digit after
a decimal point in a standard C# decimal value, WITHOUT use of any
string formatting.

Example:
5231,12231 <- Lengt = 5

Tnx for your attention hope you are capable of helping.

Kind regards
Stefan

[Stefantastisk]

Hey John,

Tnx for your reaction.

Your example is one of the most slick methods, that I also have
considered, but there is still a ToString formatting going on.

BUT it seems as, according to reactions in other groups, that it is
nearly impossible to avoid the use of string formatting.

My worries towards the use of string formatting is based on the
differences in cultural string handling and the formatting of decimals
("," or ".").

But thanks for your example.

Take care

Regards,
Stefan

On 14 Nov., 16:18, "John Timney \(MVP\)" <[e-mail]>
wrote:

You could just split it apart, without any formatting

Double start_value = 5231.12231;
string[] end_values = start_value.ToString().Split('.');
int slen = end_values[1].Length;
Response.Write(slen);

--
Regards

John Timney (MVP)
VISIT MY WEBSITE:http://www.johntimney.comhttp://www.johntimney.com/blog

"Stefantastisk" <[e-mail] in messagenews:1163514310..89***********@b28g2000cwb. googlegroups.com...

Hey there,

Anyone knows a clever method for knowing the length of the digit after
a decimal point in a standard C# decimal value, WITHOUT use of any
string formatting.

Example:
5231,12231 <- Lengt = 5

Tnx for your attention hope you are capable of helping.

Kind regards
Stefan- Skjul tekst i anførselstegn -- Vis tekst i anførselstegn -

[John Timney \(MVP\)]

The problem is your asking for a count of the number of integers, in theory
your asking for the length of a set of characters. The fact that they are
numbers is irrelevent really.

Heres an example that doesn't care about whether the seperator is . or , or
whatever, but instead assumes that the first none numeric character of the
string in reverse is the seperator, and thus concludes the char count.

Double myVal = 5231.12231;
char[] reverse = myVal.ToString().ToCharArray();
Array.Reverse(reverse);
for (int i = 0; i < reverse.Length; i++){
if (!char.IsNumber(reverse[i])){
Response.Write("Length is " + i);
}
}

--
--
Regards

John Timney (MVP)
VISIT MY WEBSITE:
http://www.johntimney.com
http://www.johntimney.com/blog

"Stefantastisk" <st***********@gmail.comwrote in message
news:11**********************@h54g2000cwb.googlegr oups.com...
Hey John,

Tnx for your reaction.

Your example is one of the most slick methods, that I also have
considered, but there is still a ToString formatting going on.

BUT it seems as, according to reactions in other groups, that it is
nearly impossible to avoid the use of string formatting.

My worries towards the use of string formatting is based on the
differences in cultural string handling and the formatting of decimals
("," or ".").

But thanks for your example.

Take care

Regards,
Stefan

On 14 Nov., 16:18, "John Timney \(MVP\)" <[e-mail]>
wrote:

You could just split it apart, without any formatting

Double start_value = 5231.12231;
string[] end_values = start_value.ToString().Split('.');
int slen = end_values[1].Length;
Response.Write(slen);

--
Regards

John Timney (MVP)
VISIT MY WEBSITE:http://www.johntimney.comhttp://www.johntimney.com/blog

"Stefantastisk" <[e-mail] in
messagenews:11**********************@b28g2000cwb.g ooglegroups.com...

Hey there,

Anyone knows a clever method for knowing the length of the digit after
a decimal point in a standard C# decimal value, WITHOUT use of any
string formatting.

Example:
5231,12231 <- Lengt = 5

Tnx for your attention hope you are capable of helping.

Kind regards
Stefan- Skjul tekst i anførselstegn -- Vis tekst i anførselstegn -

[Stefantastisk]

Hey John,

Nice snippet of code, that is a clever design regarding the
delimiter/culture issue.

Tnx mate.

Regards
Stefan

On 15 Nov., 12:54, "John Timney \(MVP\)" <[e-mail]>
wrote:

The problem is your asking for a count of the number of integers, in theory
your asking for the length of a set of characters. The fact that they are
numbers is irrelevent really.

Heres an example that doesn't care about whether the seperator is . or , or
whatever, but instead assumes that the first none numeric character of the
string in reverse is the seperator, and thus concludes the char count.

Double myVal = 5231.12231;
char[] reverse = myVal.ToString().ToCharArray();
Array.Reverse(reverse);
for (int i = 0; i < reverse.Length; i++){
if (!char.IsNumber(reverse[i])){
Response.Write("Length is " + i);
}
}

--
--
Regards

John Timney (MVP)
VISIT MY WEBSITE:http://www.johntimney.comhttp://www.johntimney.com/blog

"Stefantastisk" <[e-mail] in messagenews:1163577586..75***********@h54g2000cwb. googlegroups.com...
Hey John,

Tnx for your reaction.

Your example is one of the most slick methods, that I also have
considered, but there is still a ToString formatting going on.

BUT it seems as, according to reactions in other groups, that it is
nearly impossible to avoid the use of string formatting.

My worries towards the use of string formatting is based on the
differences in cultural string handling and the formatting of decimals
("," or ".").

But thanks for your example.

Take care

Regards,
Stefan

On 14 Nov., 16:18, "John Timney \(MVP\)" <[e-mail]>
wrote:

You could just split it apart, without any formatting

Double start_value = 5231.12231;
string[] end_values = start_value.ToString().Split('.');
int slen = end_values[1].Length;
Response.Write(slen);

--
Regards

John Timney (MVP)
VISIT MY WEBSITE:http://www.johntimney.comhttp://www.johntimney.com/blog

"Stefantastisk" <[e-mail] in
messagenews:11**********************@b28g2000cwb.g ooglegroups.com...

Hey there,

Anyone knows a clever method for knowing the length of the digit after
a decimal point in a standard C# decimal value, WITHOUT use of any
string formatting.

Example:
5231,12231 <- Lengt = 5

Tnx for your attention hope you are capable of helping.

Kind regards
Stefan- Skjul tekst i anførselstegn -- Vis tekst i anførselstegn -- Skjul tekst i anførselstegn -- Vis tekst i anførselstegn -

[John Timney \(MVP\)]

glad you like it

--
--
Regards

John Timney (MVP)
VISIT MY WEBSITE:
http://www.johntimney.com
http://www.johntimney.com/blog
"Stefantastisk" <st***********@gmail.comwrote in message
news:11**********************@m73g2000cwd.googlegr oups.com...
Hey John,

Nice snippet of code, that is a clever design regarding the
delimiter/culture issue.

Tnx mate.

Regards
Stefan

On 15 Nov., 12:54, "John Timney \(MVP\)" <[e-mail]>
wrote:

The problem is your asking for a count of the number of integers, in
theory
your asking for the length of a set of characters. The fact that they are
numbers is irrelevent really.

Heres an example that doesn't care about whether the seperator is . or ,
or
whatever, but instead assumes that the first none numeric character of the
string in reverse is the seperator, and thus concludes the char count.

Double myVal = 5231.12231;
char[] reverse = myVal.ToString().ToCharArray();
Array.Reverse(reverse);
for (int i = 0; i < reverse.Length; i++){
if (!char.IsNumber(reverse[i])){
Response.Write("Length is " + i);
}
}

--
--
Regards

John Timney (MVP)
VISIT MY WEBSITE:http://www.johntimney.comhttp://www.johntimney.com/blog

"Stefantastisk" <[e-mail] in
messagenews:11**********************@h54g2000cwb.g ooglegroups.com...
Hey John,

Tnx for your reaction.

Your example is one of the most slick methods, that I also have
considered, but there is still a ToString formatting going on.

BUT it seems as, according to reactions in other groups, that it is
nearly impossible to avoid the use of string formatting.

My worries towards the use of string formatting is based on the
differences in cultural string handling and the formatting of decimals
("," or ".").

But thanks for your example.

Take care

Regards,
Stefan

On 14 Nov., 16:18, "John Timney \(MVP\)" <[e-mail]>
wrote:

You could just split it apart, without any formatting

Double start_value = 5231.12231;
string[] end_values = start_value.ToString().Split('.');
int slen = end_values[1].Length;
Response.Write(slen);

--
Regards

John Timney (MVP)
VISIT MY WEBSITE:http://www.johntimney.comhttp://www.johntimney.com/blog

"Stefantastisk" <[e-mail] in
messagenews:11**********************@b28g2000cwb.g ooglegroups.com...

Hey there,

Anyone knows a clever method for knowing the length of the digit after
a decimal point in a standard C# decimal value, WITHOUT use of any
string formatting.

Example:
5231,12231 <- Lengt = 5

Tnx for your attention hope you are capable of helping.

Kind regards
Stefan- Skjul tekst i anførselstegn -- Vis tekst i anførselstegn --
Skjul tekst i anførselstegn -- Vis tekst i anførselstegn -