Copying A Control Not As A Reference

[Nathan Sokalski]

I have a Control that I want to copy as a copy of the Control, not a copy of
the reference to the original. My reason for doing this is because some of
the methods I would calling would prevent proper rendering afterwards. I
access the Control as a parameter of a function, as follows:

Private Function MyFunction(ByVal ctrl As Control) As String
'code that will make a copy of ctrl
'my function code
End Function

(NOTE: I am using VB.NET and .NET Framework 1.1) Thanks.
--
Nathan Sokalski
nj********@hotmail.com
http://www.nathansokalski.com/

[tomb]

Nathan Sokalski wrote:

I have a Control that I want to copy as a copy of the Control, not a copy of
the reference to the original. My reason for doing this is because some of
the methods I would calling would prevent proper rendering afterwards. I
access the Control as a parameter of a function, as follows:

Private Function MyFunction(ByVal ctrl As Control) As String
'code that will make a copy of ctrl
'my function code
End Function

(NOTE: I am using VB.NET and .NET Framework 1.1) Thanks.

You have to pass the ctrl ByRef in order to be working with the one you
want to copy.

T

[Nathan Sokalski]

That does not help. Let me try explaining my problem differently with an
example:

Private Function MyFunction(ByVal ctrl As Control) As String
dim copyofctrl as Control

'copyofctrl=ctrl this will be replaced with code that will assign a
copy of ctrl to copyofctrl that points to a new instance of whatever type
ctrl was
'my function code
End Function

In the part of my code labeled "my function code" I want to be able to do
ANYTHING I WANT to the local variable copyofctrl without having any effect
on ctrl. Hopefully this clears up what I am trying to do.
--
Nathan Sokalski
nj********@hotmail.com
http://www.nathansokalski.com/

"tomb" <to**@technetcenter.com> wrote in message
news:RV*******************@bignews8.bellsouth.net. ..

Nathan Sokalski wrote:

I have a Control that I want to copy as a copy of the Control, not a copy
of the reference to the original. My reason for doing this is because some
of the methods I would calling would prevent proper rendering afterwards.
I access the Control as a parameter of a function, as follows:

Private Function MyFunction(ByVal ctrl As Control) As String
'code that will make a copy of ctrl
'my function code
End Function

(NOTE: I am using VB.NET and .NET Framework 1.1) Thanks.

You have to pass the ctrl ByRef in order to be working with the one you
want to copy.

T

[Cor Ligthert [MVP]]

Nathan,

If a class is serializable you can almost forever copy something to
serialize the object first and than deserialize it again.

http://www.vb-tips.com/default.aspx?...c-61641f5c8d9d

I hope this helps,

Cor

"Nathan Sokalski" <nj********@hotmail.com> schreef in bericht
news:%2****************@TK2MSFTNGP02.phx.gbl...

I have a Control that I want to copy as a copy of the Control, not a copy
of the reference to the original. My reason for doing this is because some
of the methods I would calling would prevent proper rendering afterwards. I
access the Control as a parameter of a function, as follows:

Private Function MyFunction(ByVal ctrl As Control) As String
'code that will make a copy of ctrl
'my function code
End Function

(NOTE: I am using VB.NET and .NET Framework 1.1) Thanks.
--
Nathan Sokalski
nj********@hotmail.com
http://www.nathansokalski.com/

[Herfried K. Wagner [MVP]]

"tomb" <to**@technetcenter.com> schrieb:

I have a Control that I want to copy as a copy of the Control, not a copy
of the reference to the original. My reason for doing this is because some
of the methods I would calling would prevent proper rendering afterwards.
I access the Control as a parameter of a function, as follows:

Private Function MyFunction(ByVal ctrl As Control) As String
'code that will make a copy of ctrl
'my function code
End Function

(NOTE: I am using VB.NET and .NET Framework 1.1) Thanks.

You have to pass the ctrl ByRef in order to be working with the one you
want to copy.

No, you should pass it 'ByVal' because 'Control' is already a reference
type.

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://classicvb.org/petition/>