Q: convert to numbers

[JIM.H.]

Hello,

string newStr=myStr.Substring(1,3);
int newNum = System.Convert.ToInt32(newStr);

This fails if newStr does not have all characters as numbers. How can you do
this in a professional way?

Thanks,
Jim.

[Norman Yuan]

int newNum;
try
{
newNum=Convert.ToInt32(newStr);
}
cacth
{
newNum=0; //Or other default value
}

"JIM.H." <JI**@discussions.microsoft.com> wrote in message
news:BC**********************************@microsof t.com...

Hello,

string newStr=myStr.Substring(1,3);
int newNum = System.Convert.ToInt32(newStr);

This fails if newStr does not have all characters as numbers. How can you do this in a professional way?

Thanks,
Jim.

[Kevin Spencer]

You can check if it is a number by using Int32.Parse() and a try/catch. If
it raises an exception, you handle it and it isn't a number.

--
HTH,

Kevin Spencer
Microsoft MVP
..Net Developer
Ambiguity has a certain quality to it.

"JIM.H." <JI**@discussions.microsoft.com> wrote in message
news:BC**********************************@microsof t.com...

Hello,

string newStr=myStr.Substring(1,3);
int newNum = System.Convert.ToInt32(newStr);

This fails if newStr does not have all characters as numbers. How can you
do
this in a professional way?

Thanks,
Jim.

[Scott Allen]

You'll have to place the Convert.ToInt32 call inside of a try / catch
block. In 2.0 there will be TryParse methods that don't throw.

--
Scott
http://www.OdeToCode.com/blogs/scott/

On Fri, 3 Jun 2005 12:05:16 -0700, JIM.H.
<JI**@discussions.microsoft.com> wrote:

Hello,

string newStr=myStr.Substring(1,3);
int newNum = System.Convert.ToInt32(newStr);

This fails if newStr does not have all characters as numbers. How can you do
this in a professional way?

Thanks,
Jim.

[Scott Allen]

.... or write your own IsNumeric method ...

--
Scott
http://www.OdeToCode.com/blogs/scott/

On Fri, 3 Jun 2005 12:05:16 -0700, JIM.H.
<JI**@discussions.microsoft.com> wrote:

Hello,

string newStr=myStr.Substring(1,3);
int newNum = System.Convert.ToInt32(newStr);

This fails if newStr does not have all characters as numbers. How can you do
this in a professional way?

Thanks,
Jim.