"if" question

[Miguel Dias Moura]

Hello,

i have this code line in a script in my ASP.net / VB web site:

if msgNewsletterAction = "Go" Then
code1
Else
code2
End If

code2 runs everytime even when msgNewsletterAction = "Go". code1 never runs.

What is wrong in my sintax?

Thank You,
Miguel

[AT]

"Miguel Dias Moura" <in************@27lamps.com> wrote in message
news:%2***************@TK2MSFTNGP11.phx.gbl...

Hello,

i have this code line in a script in my ASP.net / VB web site:

How msgNewsletterAction is declared?
Try msgNewsletterAction.ToString()

But msgNewsletterAction can be anything so please add info

if msgNewsletterAction = "Go" Then
code1
Else
code2
End If

code2 runs everytime even when msgNewsletterAction = "Go". code1 never runs.
What is wrong in my sintax?

Thank You,
Miguel

[Miguel Dias Moura]

Hi,

i declared the variable as follows:

dim msgNewsletterAction

then i got the value from a form:

msgNewsletterAction = Request.Form("newsletterAction")

then i sent the value to an email using AspNetEmail. I readed my email and
there it was...the word "Go".

This is why this is so strange.

Thanks,
Miguel

"AT" <an*****@avwork.com> wrote in message
news:eJ**************@TK2MSFTNGP11.phx.gbl...

"Miguel Dias Moura" <in************@27lamps.com> wrote in message
news:%2***************@TK2MSFTNGP11.phx.gbl...

Hello,

i have this code line in a script in my ASP.net / VB web site:

How msgNewsletterAction is declared?
Try msgNewsletterAction.ToString()

But msgNewsletterAction can be anything so please add info

if msgNewsletterAction = "Go" Then
code1
Else
code2
End If

code2 runs everytime even when msgNewsletterAction = "Go". code1 never

runs.

What is wrong in my sintax?

Thank You,
Miguel

[Martin]

you need to declare as a string if you are checking for a string, I think you have it as a variant type so could try .toString but would be better to delcare a correct type

[Miguel Dias Moura]

How can i declare it as a sting?

Thank You,
Miguel

"Martin" <an*******@discussions.microsoft.com> wrote in message
news:A8**********************************@microsof t.com...

you need to declare as a string if you are checking for a string, I think

you have it as a variant type so could try .toString but would be better to
delcare a correct type