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problem in binding child datagrid

15 New Member
Hi

I am receiving Object reference not set to an instance of an Object when binding Child dataGrid in the ItemCommandEven t of Parent dataGrid.

Can someone please guide me what is wrong in the code below?

I checked the table size and it is 2. Please advise

Thanks

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  1. <asp:datagrid id="DataGrid1" runat="server" Height="176px" AutoGenerateColumns="False">
  2. <Columns>
  3.    <asp:BoundColumn Visible="False" DataField="eveid" HeaderText="EventId"></asp:BoundColumn>
  4.    <asp:BoundColumn Visible="False" DataField="conid" HeaderText="ContactId"></asp:BoundColumn>
  5.  
  6. <asp:TemplateColumn HeaderText="Source">
  7.   <ItemTemplate>
  8.     <asp:DropDownList id="Dropdownlist2" runat="server" >
  9.                             <asp:ListItem Value="--Select--" Selected="True">--Select--</asp:ListItem>
  10.                                 <asp:ListItem Value="Web">Web</asp:ListItem>
  11.                                 <asp:ListItem Value="Email">Email</asp:ListItem>
  12.                                 <asp:ListItem Value="Phone">Phone</asp:ListItem>
  13.                                 <asp:ListItem Value="Other">Other</asp:ListItem>
  14.                             </asp:DropDownList>
  15.                         </ItemTemplate>
  16. </asp:TemplateColumn>
  17. <asp:TemplateColumn HeaderText="Detail">
  18. <ItemTemplate>
  19. <P>                    
  20. <asp:TextBox id="TextBox2" runat="server"></asp:TextBox>
  21. <asp:TextBox id="Textbox1" runat="server" Visible="False"></asp:TextBox>
  22. <asp:Button id="Button2" runat="server" Text="Search" CommandName="Search"></asp:Button></P>
  23. <P>
  24. <asp:Label id="Label13" runat="server" Visible="False" ForeColor="Red">Label</asp:Label></P>
  25. </ItemTemplate>
  26. <EditItemTemplate>
  27. <asp:DataGrid id="DataGrid2" runat="server"></asp:DataGrid>
  28. </EditItemTemplate>
  29. </asp:TemplateColumn>
  30. </Columns>
  31. </asp:datagrid>

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  1. private void ItemsGrid_Command(object source, System.Web.UI.WebControls.DataGridCommandEventArgs e)
  2. {
  3. DataTable dt=new DataTable();
  4. DataRow dr;
  5. dt.Columns.Add("AcId",Type.GetType("System.String"));
  6. dt.Columns.Add("AcName",Type.GetType("System.String"));
  7. dt.Columns.Add("AcAddress",Type.GetType("System.String"));
  8. dt.Columns.Add("AcOwner",Type.GetType("System.String"));
  9.  
  10. switch(e.CommandName)
  11. {
  12. case "Search":
  13. try
  14. {    
  15. TextBox txt=(TextBox)(e.Item.Cells[8].FindControl("TextBox2"));
  16. DropDownList ddl=(DropDownList)(e.Item.Cells[5].FindControl("Dropdownlist2"));
  17. Label lbl=(Label)(e.Item.Cells[8].FindControl("Label13"));
  18. DataGrid dg2=(DataGrid)(e.Item.Cells[5].FindControl("DataGrid2"));
  19.  
  20. if(ddl.SelectedValue == "" || ddl.SelectedValue == "--Select--")
  21. {
  22. lbl.Text="Please select Source";
  23. lbl.Visible=true;
  24. }
  25. else
  26. {
  27. if(login())
  28.  {
  29. string Acct_query="Select Id,Name,BillingStreet,Billingcity,BillingState,BillingPostalCode,Owner.Name from Account where RECORDTYPEID='0123000000005QB' and Ownerid='"+Session["UserID"].ToString()+"' and name like '%"+ddl.SelectedValue+"%' ";
  30.  
  31. QueryResult qr = binding.query(Acct_query); 
  32. sObject[] records = qr.records;
  33. if(qr.size>0)
  34. {
  35.                               for (int i=0; i<records.Length; i++) 
  36. {
  37. Account acc = (Account)records[i];
  38. dr=dt.NewRow();
  39. dr["AcId"]=acc.Id;
  40. dr["AcName"]=acc.Name;
  41. dr["AcAddress"]=acc.BillingStreet;
  42. dr["AcOwner"]=acc.Owner.Name;
  43. dt.Rows.Add(dr);
  44. }
  45. dg2.DataSource=dt;
  46. dg2.DataBind();
  47. }
  48. else
  49. {
  50. }
  51.  }
  52. }
  53.  
  54. }
  55. catch(Exception ex)
  56. {
  57. Response.Write(ex.Message.ToString());
  58. }
  59. break;
  60. default:
  61. break;
  62. }
  63. }
Mar 12 '10 #1
1 2235
tlhintoq
3,525 Recognized Expert Specialist
"How do I fix a 'object reference not set to an instance of an object' error?
The line your code stopped on while debugging holds all your answers.
One of the variables/objects was created but not initialized. For example:
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  1. string TempString;// Created but not initialized so this is still null
  2. //versus
  3. string TempString = string.empty;
Debug your project again. This time, when it breaks on a line look at the Locals pallet to see which variable/object is null. You can also hover your mouse over each variable and the hothelp will shows its value. One of them will be null.
Mar 12 '10 #2

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