How to Write This Function

[serdar]

Hi,

I have a function y=1/x but I need it to return values like:

y=1.0 --> x=1.0
y=0.5 --> x=1.5

I guess I need a logarithmic function but how?

Thanks.

[JosAH]

@serdar
Any function that goes through those two points (1.0,1.1.0) and (1.5, 0.5) will do, even a simple linear function f(x) == 2-x would do fine. What exactly do you want?

kind regards,

Jos

[serdar]

I have a multiplier variable that changes based on a percentage value. With my current function (y=1/x) when we have 50% the multiplier is 2, which is too high for me.

[JosAH]

@serdar
What would the values f(0) and f(infinity) be for your function?

kind regards,

Jos

[serdar]

Well the multiplier is actually a 'gain' value depends on the volume. So if the volume is 0 there is no need to calculate the gain.

gain=1/volume; (where volume>0 and volume<=1)

[jkmyoung]

x = - log(y) + 1 ??
y = 1 -> x = 1
y = .5 -> x = 1.30
y = .2 -> x = 1.70

or
x = -ln(y) + 1 ??
y = 1 -> x = 1
y = .5 -> x = 1.69
y = .2 -> x = 2.61

[serdar]

Thanks jkmyoung, I'll look deeper into that when I'm back working on the project.

[wbgxx]

can someone give a detail??