How to open form2 and then return to the same previous record in form1?

[neelsfer]

I open a 2nd form called "Fis_StEditF" from the subform where i am currently capturing called
"[Forms]![stocktakeF]![Fis_StocktakeSF]",
using the code below, where "icn" is the same for both.

This works and i go to the correct record.

DoCmd.OpenForm "Fis_StEditF", acNormal, "", "[icn]=" & "" & Icn & "", , acNormal

On pressing the Close button in the "Fis_StEditF" form, i want to return to the same line (last record captured) in "[Forms]![stocktakeF]![Fis_StocktakeSF]", where i was busy capturing before i went to "Fis_StEditF"
The main "field" in "Fis_StocktakeSF" is called "item_lookup"
pls help.

[neelsfer]

In the previous post i opened the "Fis_StEditF" form and it showed the correct record. Now I would like to return to the last record in the "Fis_StocktakeSF" where i came from, to update the current table with that last record.
I am struggling with this setfocus as it moves to the next blank record when i update via me.name = me.name function and add this blank record to the table.
I have an Id field called STId in both tables, that is the same and can be used as a reference to refer to each other.

Private Sub upd_Click()
On Error GoTo upd_Click_Err
[Forms]![stocktakeF]![Fis_StocktakeSF].SetFocus
DoCmd.GoToRecord , , acLast
Bincard_Total = [Forms]![stocktakeF]![Fis_StocktakeSF]![Bincard_Total]
BeginStock = [Forms]![stocktakeF]![Fis_StocktakeSF]![BeginStock]
FirstCount = [Forms]![stocktakeF]![Fis_StocktakeSF]![FirstCount]
SecondCount = [Forms]![stocktakeF]![Fis_StocktakeSF]![SecondCount]
ConfirmedCount = [Forms]![stocktakeF]![Fis_StocktakeSF]![ConfirmedCount]
 
    DoCmd.RunCommand acCmdRefresh
upd_Click_Exit:
    Exit Sub
 
upd_Click_Err:
    MsgBox Error$
    Resume upd_Click_Exit
 
End Sub