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Counting rows

P: 2
Hello,

I have a table with the below data:

ID Cat Rat Rabbits

001 A B D
002 A C E
003 B A A
004 A E B
005 D A B
006 B C A

I want to count the # of A,B,C,D and E's from each column.
Expand|Select|Wrap|Line Numbers
  1. SELECT cat,sum(Abs(cat="A" or "B" or "C" or "D")) as Cat_Tot
  2. from sample
  3. group by cat
The above query works for single column.

Output sample.
Cat Count Rat Count Rabbits Count
A 2 A 2 A 1
B 2 B 1 C 2

Can anyone help with this please?
Oct 10 '08 #1
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4 Replies


puppydogbuddy
Expert 100+
P: 1,923
try it this way:
Expand|Select|Wrap|Line Numbers
  1. SELECT cat,sum(Abs(cat="A" or cat="B" or cat="C" or cat="D")) as Cat_Tot
  2. from sample
  3. group by cat
if the above does not work, try this:
Expand|Select|Wrap|Line Numbers
  1. SELECT cat,sum(Abs(IIf(cat="A" or cat="B" or cat="C" or cat="D"))) as Cat_Tot
  2. from sample
  3. group by cat
Oct 12 '08 #2

NeoPa
Expert Mod 15k+
P: 31,707
I can't believe this is possible to achieve in SQL (without breaking it up into three different queries and UNIONing the results together).

How can it be when you'd need to GROUP BY all three columns independently.

I will look into a solution for you.
Oct 12 '08 #3

NeoPa
Expert Mod 15k+
P: 31,707
This will be complicated anyway. Do you have a table which contains all the possible "letter"s that you want to report on? Without this the resulting SQL will be quite extraordinarily complex.
Oct 12 '08 #4

NeoPa
Expert Mod 15k+
P: 31,707
Assuming there is such a table ([tblLetters] with field [Letter]) then try :
Expand|Select|Wrap|Line Numbers
  1. SELECT Letter
  2.        Sum(Cats) AS NoCats,
  3.        Sum(Rats) AS NoRats,
  4.        Sum(Rabbits) AS NoRabbits
  5.  
  6. FROM (SELECT tL.Letter,
  7.              Count(tL.Letter) AS Cats,
  8.              0 AS Rats,
  9.              0 AS Rabbits
  10.  
  11.       FROM [tblLetters] AS tL INNER JOIN [Sample] AS tS
  12.         ON tL.Letter=tS.Cat
  13.  
  14.       GROUP BY tL.Letter
  15.  
  16.       UNION ALL
  17.       SELECT tL.Letter,
  18.              0 AS Cats,
  19.              Count(tL.Letter) AS Rats,
  20.              0 AS Rabbits
  21.  
  22.       FROM [tblLetters] AS tL INNER JOIN [Sample] AS tS
  23.         ON tL.Letter=tS.Rat
  24.  
  25.       GROUP BY tL.Letter
  26.  
  27.       UNION ALL
  28.       SELECT tL.Letter,
  29.              0 AS Cats,
  30.              0 AS Rats,
  31.              Count(tL.Letter) AS Rabbits
  32.  
  33.       FROM [tblLetters] AS tL INNER JOIN [Sample] AS tS
  34.         ON tL.Letter=tS.Rabbits
  35.  
  36.       GROUP BY tL.Letter
  37.  
  38.       ORDER BY tL.Letter) AS subQ
  39.  
  40. GROUP BY [Letter]
You can probably see that doing this without a table to use as [tblLetters] would be somewhat convoluted.
Oct 12 '08 #5

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