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Soap 3.0

Hi

Is it possible to use soap 3 with access? Basically I need to use code like
this;

Dim oSOAP As New MSSOAPLib30.SoapClient30
Dim sResult As String

oSOAP.ClientProperty("ServerHTTPRequest") = True
Call oSOAP.MSSoapInit("http://ws.textanywhere.net/ta_SMS.asmx?wsdl")
sResult = oSOAP.SomeMethod(<parameters here>)
Set oSOAP = Nothing

Thanks

Regards
Nov 13 '05 #1
2 3446
rkc

"John" <Jo**@nospam.infovis.co.uk> wrote in message
news:41***********************@news-text.dial.pipex.com...
Hi

Is it possible to use soap 3 with access? Basically I need to use code like this;

Dim oSOAP As New MSSOAPLib30.SoapClient30
Dim sResult As String

oSOAP.ClientProperty("ServerHTTPRequest") = True
Call oSOAP.MSSoapInit("http://ws.textanywhere.net/ta_SMS.asmx?wsdl")
sResult = oSOAP.SomeMethod(<parameters here>)
Set oSOAP = Nothing


What is preventing you from trying this and finding out for yourself?

Seems to me all you'd have to do is set a reference to the correct
library and have at it.


Nov 13 '05 #2
Do a search for "consuming web services" in this group and you will
find a link to some microsoft articles that explain how to do this.
The article is from Nov 22, 2004

I followed these examples and got it working no problem...

"rkc" <rk*@yabba.dabba.do.rochester.rr.bomb> wrote in message news:<VE******************@twister.nyroc.rr.com>.. .
"John" <Jo**@nospam.infovis.co.uk> wrote in message
news:41***********************@news-text.dial.pipex.com...
Hi

Is it possible to use soap 3 with access? Basically I need to use code

like
this;

Dim oSOAP As New MSSOAPLib30.SoapClient30
Dim sResult As String

oSOAP.ClientProperty("ServerHTTPRequest") = True
Call oSOAP.MSSoapInit("http://ws.textanywhere.net/ta_SMS.asmx?wsdl")
sResult = oSOAP.SomeMethod(<parameters here>)
Set oSOAP = Nothing


What is preventing you from trying this and finding out for yourself?

Seems to me all you'd have to do is set a reference to the correct
library and have at it.

Nov 13 '05 #3

This thread has been closed and replies have been disabled. Please start a new discussion.

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