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full outer join on two tables

i have two tables, Event1 and Event2.
They both have fields called contactID and eventID in them.
Some of the contactID's between the tables are equal and some are not.
I want to do a full outer join on contactID so i can get all the
contactID's in the query.

i know access doesn't support full outer joins so there must be a way to
do it without using one.

how do you do it in access 2000?

thanks in advance,

Cory
Nov 13 '05 #1
2 7440
Cory,
Create a union of a left and a right join, so:
SELECT ACTIVE_EVENT.CONTACTID, ACTIVE_EVENT.EVENTID
FROM EVENT1 AS ACTIVE_EVENT
LEFT JOIN EVENT2 AS CLOSED_EVENT
ON ACTIVE_EVENT.CONTACTD = CLOSED_EVENT.CONTACTID
AND ACTIVE_EVENT.EVENTID = CLOSED_EVENT.EVENTID
UNION
SELECT CLOSED_EVENT.CONTACTID, CLOSED_EVENT.EVENTID
FROM EVENT1 AS ACTIVE_EVENT
RIGHT JOIN EVENT2 AS CLOSED_EVENT
ON ACTIVE_EVENT.CONTACTD = CLOSED_EVENT.CONTACTID
AND ACTIVE_EVENT.EVENTID = CLOSED_EVENT.EVENTID

"Cory" <no@no.com> wrote in message
news:1W******************@news02.tsnz.net...
i have two tables, Event1 and Event2.
They both have fields called contactID and eventID in them.
Some of the contactID's between the tables are equal and some are not.
I want to do a full outer join on contactID so i can get all the
contactID's in the query.

i know access doesn't support full outer joins so there must be a way to
do it without using one.

how do you do it in access 2000?

thanks in advance,

Cory

Nov 13 '05 #2
Cory <no@no.com> wrote in
news:1W******************@news02.tsnz.net:
i have two tables, Event1 and Event2.
They both have fields called contactID and eventID in them.
Some of the contactID's between the tables are equal and some
are not. I want to do a full outer join on contactID so i can
get all the contactID's in the query.

i know access doesn't support full outer joins so there must
be a way to do it without using one.

how do you do it in access 2000?

thanks in advance,

Cory


I create a union query for the desired field from each table, and
then left outer join that table back to each source.

Bob Quintal
Nov 13 '05 #3

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