FindFirst and Apostrophe

[Mark]

I get "error 3077 Syntax Error (missing operator) in expression" in this
expression:
Rst.FindFirst "[Section]='" & Me!NewSection & "'"
when Me!NewSection contains an apostrophe.

How can I write the FindFirst expression so it works whether or not
Me!NewSection contains an apostrophe?

Thanks!

Mark

[Duane Hookom]

Try:
Rst.FindFirst "[Section]=""" & Me!NewSection & """"
--
Duane Hookom
MS Access MVP
"Mark" <mm*****@Earthlink.net> wrote in message
news:Im*****************@newsread2.news.atl.earthl ink.net...

I get "error 3077 Syntax Error (missing operator) in expression" in this
expression:
Rst.FindFirst "[Section]='" & Me!NewSection & "'"
when Me!NewSection contains an apostrophe.

How can I write the FindFirst expression so it works whether or not
Me!NewSection contains an apostrophe?

Thanks!

Mark

[Bradley]

Mark wrote:

I get "error 3077 Syntax Error (missing operator) in expression" in
this expression:
Rst.FindFirst "[Section]='" & Me!NewSection & "'"
when Me!NewSection contains an apostrophe.

How can I write the FindFirst expression so it works whether or not
Me!NewSection contains an apostrophe?

Thanks!

Mark

Don't use the apostraphe as your text delimiter, use the double quote
character:

Rst.FindFirst "[Section]=" & Chr(32) & Me!NewSection & Chr(32)

ps. Perhaps don't cross-post either! :)
--
regards,

Bradley

[Trevor Best]

Mark wrote:

I get "error 3077 Syntax Error (missing operator) in expression" in this
expression:
Rst.FindFirst "[Section]='" & Me!NewSection & "'"
when Me!NewSection contains an apostrophe.

How can I write the FindFirst expression so it works whether or not
Me!NewSection contains an apostrophe?

As others have said the double quote thing, that can bring about the
same problem if your text contains a double quote. The answer is to
double up your quotes, e.g.

Rst.FindFirst "[Section]='" & Replace(Me!NewSection,"'","''") & "'"

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