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Open File in other folder

P: n/a
(Access 2000)

I have:

Set eWB = e.Workbooks.Open("Book1.xls")

Where e is DIM'd as an Excel.Application and eWB as an Excel.Workbook.

This file opens fine.

This file is in folder "ThisFolder" along with the .mdb file.

Now, my question concerns, how do I get a file that is in a folder one
up, such as "UpperFolder" is the name of the folder that contains
"ThisFolder" and "Book2.xls" is in "UpperFolder".


- Bruce

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Nov 12 '05 #1
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2 Replies

P: n/a
how about passing the full path to the file?
Nov 12 '05 #2

P: n/a
> Set eWB = e.Workbooks.Open("Book1.xls")
This file opens fine.

Are you sure? I have to provide the full path like
"C:\ThisFolder\Book1.xls", otherwise it won't work, even with a
ChDir "C:\ThisFolder\" before.


No mails please.
Nov 12 '05 #3

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