xsl:how to traverse through a loop and increment the counter each time for all rows

I tried the below:-
No. of Rows: - <xsl:value-of select="$rowcount"/>

Now i used -->
How the counter or position will get incremented and i can display all the rows correctly?

re: xsl:how to traverse through a loop and increment the counter each time for all rows

I didn’t understand, can you elaborate that?

re: xsl:how to traverse through a loop and increment the counter each time for all rows

--> [My answer]
I want to display all the rows of a table till the end of table is encountered.

So, in a way need to traverse through the loop and display first row and then automatically position() or counter should be incremented and then display the second row in the second line and so on....

Suppose no. of rows in a table = 10
Header --> A B C
row1 --> 10 abc 20
row2 --> 20 def 10
....
....
row10 --> 30 xyz 40

Please let me know how to achieve the above output?

re: xsl:how to traverse through a loop and increment the counter each time for all rows

something like

re: xsl:how to traverse through a loop and increment the counter each time for all rows

-->
I tried the below
Now i do not getting any values displayed....

re: xsl:how to traverse through a loop and increment the counter each time for all rows

of course. I doubt that DBE:Attribute is a child of DBE:TableRow.

re: xsl:how to traverse through a loop and increment the counter each time for all rows

Yes, you are right. The first and the third columns are children of DBE:TableRow while the second column is DBE:Attribute. (in below table)

Header --> A B C
row1 --> 10 abc 20
row2 --> 20 def 10


So, is there any way that i initialize n=1 then traverse a loop until the total count of rows in the table and display the values -->