XSL Display a Table

prao2005

Q) How to display all the records of a table using xsl?

Solution applied -->
Suppose a class "test" has an attribute "test1" which itself is a table. "test1"
contains some a1, a2, a3 attributes. I need to display all rows based on the value of an attribute"a1"

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 <xsl:template name="rowCounter">

  <xsl:param name="N" />

  <tr>

    <xsl:if test="

      DBE:Attribute[@name='a1']/

      DBE:Object[@Class='test']/

      DBE:Attribute[@name='test1']/

      DBE:Table/

      DBE:TableRow[ $N ]

    "> 

      <xsl:for-each select="

        DBE:Attribute[@name='a1']/

        DBE:Object[@Class='test']/

        DBE:Attribute [@name='test1']/

        DBE:Table

      ">

        <td>          

          <xsl:apply-templates select="DBE:TableRow[ $N ]"/>

        </td>

        <xsl:text> </xsl:text>

      </xsl:for-each>

      <xsl:call-template name="rowCounter">

        <xsl:with-param name="N" select="$N + 1"/>

      </xsl:call-template>

    </xsl:if>

  </tr>

</xsl:template>

Is the above correct? How do I display values of a1, a2 and a3 for each a1?