XSL Attribute Test

prao2005

Q) How to check whether the value of an attribute is not null or if the lenght of characters in the value of an attribute is greater than 0?

Solution applied -->
s0SelectedSite is an attribute of a class or a column of a table.

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 <xsl:if test="string-length(@s0SelectedSite) &gt; '0'">

<tr>

  <td width="50%" bgcolor="#C0C0C0"><font size="2"><b>Selected Site:</b></font></td>

  <td><font size="2">*<xsl:apply-templates select="DBE:Attribute   [@name='s0SelectedSite']"/></font></td>

</tr> 

</xsl:if>

In the above, the value of s0SelectedSite exists but still the lines are not getting printed.

For eg. It should display the following:-

Selected Site: Singapore
Please let me know if something is wrong.

Dormilich

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<xsl:apply-templates select="DBE:Attribute[@name='s0SelectedSite']"/>

what is that supposed to do?

prao2005

Its purpose is to display the the value of s0SelectedSite attribute which belong to a class/object.

Dormilich

does it do what it is supposed to do?

prao2005

Thanks to all....

0
I tried this way now --> It worked for me :

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 <xsl:choose>

  <xsl:when test="string-length(DBE:Attribute[@name='s0SelectedSite']/node()) &gt; 0"> 

    <table>

...<tr> 

  <td width="50%" bgcolor="#C0C0C0"><font size="2"><b>Selected Site:</b></font></td> 

  <td><font size="2">*<xsl:apply-templates select="DBE:Attribute   [@name='s0SelectedSite']"/></font></td> 

</tr>

    </table>

  </xsl:when>

  <xsl:otherwise>

    <table>

...<tr> 

  <td width="50%" bgcolor="#C0C0C0"><font size="2"><b>Selected Site:</b></font></td> 

  <td><font size="2">*<xsl:apply-templates select="DBE:Attribute   [@name='s0SelectedSite']"/></font></td> 

</tr>

    </table>

  </xsl:otherwise>

</xsl:choose>

It works now.....i get the field empty incase of no value....incase of value i get the selected site value.