xsl:copy-of not copy element name?

I'm using xsl:copy-of because I need to preserve a break tag in my 'description' element (see below). While it does work, it also copies over the <description> tags and puts them in my HTML, which obviously cannot pass W3C validation. Is there any way to copy everything, except for the <description> tags. Or is there a better way? I'm new at this. Thanks...

Sample from .xml file

<item id="MGEBSK">
<title>A Product Title</title>
<description>A Description that is <br/> really important.</description>
</item>


Sample from .xsl transformation file

<xsl:copy-of select="description"/>


HTML output (will not validate):

<description>A Description that is <br/> really important.</description>

Desired HTML output:

A Description that is <br/> really important.

re: xsl:copy-of not copy element name?

try
regards

PS please use [code] tags when posting code, it's much better readable this way

re: xsl:copy-of not copy element name?

Thanks, that worked great!

Any idea why it changed my break tag from <br/> to <br>? Can that be prevented?

Sorry about the [code] tags... I'll make a note of that.

re: xsl:copy-of not copy element name?

you're probably using html output method.

yes, use xml output method.

re: xsl:copy-of not copy element name?

Great! Thanks for your help!