I'm newbie to xml
I have an xml grammer file contain image files, i have to display the contents with an
xsl file.
The issue is when i mouseover the images i need to display the corresponding images from
that xml file which i'm not able to get. I'm giving piece of code of xml and xsl files.Could
u please tell me how can I get that work done
my xml file is like this--------------------------------
- <solutions name ="infrastructure solutions"
-
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icon="icons_C2/logo_infrastructure.gif" >
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<Product Name="Automation Documentation Home Page" Icon="icons_C2/home/homelogoCAA.gif"/>
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<Product Name=" Infrastructure User Guide" Icon="icons_C2/home/homelogobas.gif"/>
-
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<Product Name="Product Structure" Icon="icons_C2/home/homelogopst.gif"/>
-
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<Product Name="Real Time Rendering" Icon="icons_C2/home/homelogort1.gif"/>
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</solutions>
-
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<solutions name =" ..............">
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</solutions>
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XSL code for this is
- <xsl:for-each select="Home/solutions">
-
<tr>
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<td><img src="{@icon}" name="{@name}" onmouseover='<xsl:for-each select="Product"/>
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<td><img src="{@Icon}"/></td>
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</xsl:for-each>;'/></td>
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</tr>
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</xsl:for-each>
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this way or write a javascript function which will do the similar functionality of xsl
transolation(xsl transolation in javascript method is not possible)
- <xsl:for-each select="Home/solutions">
-
<tr>
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<td><img src="{@icon}" name="{@name}" onmouseover='iconVisible()'/> </td>
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</tr>
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-
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</xsl:for-each>
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<script language="Javascript"
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function iconVisible()
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{
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<tr>
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<xsl:for-each select="Home/solutions/Product">
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<td><img src="{@Icon}"/></td>
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</xsl:for-each>
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</tr>
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</script>
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-->
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}
-
I need to display all the solution icons on the left handside.
When I mouseover those icons i need to display corresponding product icons.
Similarly on mouseout icons should be hidden.
Thanks in advance.
