DataGridView behave different when created at runtime?

almisba7

Hi,
I am using the follwoing code to generate Menustrip at runtime.

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Dim dgv1 As DataGridView

dgv1 = Me.MenuDataGridView

ReadMenuInGridView(dgv1)

Dim MItems As New SortedList(Of String, ToolStripMenuItem)

For Each dgr As DataGridViewRow In dgv1.Rows

   Dim MItem As New ToolStripMenuItem()

   MItem.Text = dgr.Cells("item_title").Value

   MItem.Tag = dgr.Cells("item_key").Value

   MItems.Add("M" & dgr.Cells("itemid").Value, MItem)

   If dgr.Cells("parent_itemid").Value = 0 Then

      Me.GUMenuStrip.Items.Add(MItem)

      AddHandler MItem.Click, AddressOf Me.MenuClick

   ElseIf MItems.ContainsKey("M" & dgr.Cells("parent_itemid").Value) Then

      MItems.Item("M" & dgr.Cells("parent_itemid").Value).DropDownItems.Add(MItem)

      AddHandler MItem.Click, AddressOf Me.MenuClick

   End If

Next

Where the sub "ReadMenuInGridView" passes the DGV by reference and populates it with the menu item from the database.
My question is,, the program as it is in the form listed above works fine (where I have a DGV "MenuDataGridView" created at design time), however, if I want to make it 100% dynamic and use a DGV created at run time I will not get the menu? Actually the program will not get in to the For loop?
Simply to do that we can replace the first 2 statement with:

Expand|Select|Wrap|Line Numbers

 
Dim dgv1 As New DataGridView

'dgv1 = Me.MenuDataGridView

Any ideas?

Plater

Well if you are correctly creating the DataGridView as you see it being created in the designer code, there should be functionaly no difference.

almisba7

If you mean set the Run-Time-DGV properties right, then the question "what property could cause this"?

Frinavale

Quote:

Originally Posted by almisba7

Hi,
I will not get the menu? Actually the program will not get in to the For loop?
Simply to do that we can replace the first 2 statement with:

Expand|Select|Wrap|Line Numbers

 
Dim dgv1 As New DataGridView

'dgv1 = Me.MenuDataGridView

Any ideas?

You have to add the dynamic DataGridView to the Form before you can see it.

Could this be your problem?

-Frinny

almisba7

Quote:

You have to add the dynamic DataGridView to the Form before you can see it.

I don't want to see the DGV on my form. I am just using it to populate my MenuStrip "GUMenuStrip" from the database. Note that "GUMenuStrip" is created at design time, and I am OK with that.

Right now I do have the DGV "MenuDataGridView" added to the form at design time, but I have its "Visible" property = False. However, what I want to do is to have the DGV created at runtime instead. But, as I am mentioning in my first post:

Quote:

if I want to make it 100% dynamic and use a DGV created at run time I will not get the menu? Actually the program will not get in to the For loop?

???

Frinavale

I would recommend not using a DataGridView simply to load a menu strip with dynamic data. It's over complicated and not necessary.

Check out this article. It covers how to add menu items dynamically and how to reuse the MenuStrip in several different forms.

DataGridView behave different when created at runtime?

re: DataGridView behave different when created at runtime?

re: DataGridView behave different when created at runtime?

re: DataGridView behave different when created at runtime?

re: DataGridView behave different when created at runtime?

re: DataGridView behave different when created at runtime?

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