I'm converting a C# program to VB.net, but i'm having
problems converting a integer to a byte in the same way as
the c# program does.
//C# program
int i = 137694;
byte b = (byte) i;
//b returns as value 222
'VB program
dim i as integer = 137694
dim b as byte = CByte(i)
'b returns Overflow Error
I understand that the CByte function only takes values
from 0 - 255, which is why the overflow error, but the c#
program casts from int to byte and gets a value of 222.
Anyone know how to get my VB.net app to do this?
9  38440 
Well, it seems like the VB.Net way is technically correct, insofar as you
can't (correctly) cast a number greater than 255 to a byte. But if you're
just looking to extract the least-significant byte out of a longer number,
try using this formula in your code:
X Mod 256
With X being any integer.
E.g., 137694 Mod 256 = 222.
"Dante" <da******@hotmail.com> wrote in message
news:03****************************@phx.gbl... I'm converting a C# program to VB.net, but i'm having
problems converting a integer to a byte in the same way as
the c# program does.
//C# program
int i = 137694;
byte b = (byte) i;
//b returns as value 222
'VB program
dim i as integer = 137694
dim b as byte = CByte(i)
'b returns Overflow Error
I understand that the CByte function only takes values
from 0 - 255, which is why the overflow error, but the c#
program casts from int to byte and gets a value of 222.
Anyone know how to get my VB.net app to do this?
Dante,
In addition to Robert's comments (which I would recommend doing).
Remember that by default that overflow checking is on in VB.NET while it is
off by default in C#. Hence the exception in VB.NET, while truncation in C#.
Unfortunately the option to change overflow checking is at the project
level, not file, function, or statement level, which is why I would
recommend using the Mod operator as Robert suggests.
Hope this helps
Jay
"Dante" <da******@hotmail.com> wrote in message
news:03****************************@phx.gbl... I'm converting a C# program to VB.net, but i'm having
problems converting a integer to a byte in the same way as
the c# program does.
//C# program
int i = 137694;
byte b = (byte) i;
//b returns as value 222
'VB program
dim i as integer = 137694
dim b as byte = CByte(i)
'b returns Overflow Error
I understand that the CByte function only takes values
from 0 - 255, which is why the overflow error, but the c#
program casts from int to byte and gets a value of 222.
Anyone know how to get my VB.net app to do this?
Thanks, that works great, except for negative numbers do
not seem to work.
for example:
-10471344 mod 256 = -176
and in the c# program the value of -10471344 casted to a
byte is equal to 80 -----Original Message-----
Well, it seems like the VB.Net way is technically
correct, insofar as youcan't (correctly) cast a number greater than 255 to a
byte. But if you'rejust looking to extract the least-significant byte out of
a longer number,try using this formula in your code:
X Mod 256
With X being any integer.
E.g., 137694 Mod 256 = 222.
"Dante" <da******@hotmail.com> wrote in message
news:03****************************@phx.gbl... I'm converting a C# program to VB.net, but i'm having
problems converting a integer to a byte in the same way
as the c# program does.
//C# program
int i = 137694;
byte b = (byte) i;
//b returns as value 222
'VB program
dim i as integer = 137694
dim b as byte = CByte(i)
'b returns Overflow Error
I understand that the CByte function only takes values
from 0 - 255, which is why the overflow error, but the
c# program casts from int to byte and gets a value of 222.
Anyone know how to get my VB.net app to do this?
.
Dante,
Then you will need to 'normalize' it with a method other than the Mod
operator. (repeated subtraction or addition comes to mind).
Or keep that module in C#.
Or turn off the overflow checking.
Hope this helps
Jay
"Dante" <da******@hotmail.com> wrote in message
news:04****************************@phx.gbl... Thanks, that works great, except for negative numbers do
not seem to work.
for example:
-10471344 mod 256 = -176
and in the c# program the value of -10471344 casted to a
byte is equal to 80
-----Original Message-----
Well, it seems like the VB.Net way is technically
correct, insofar as youcan't (correctly) cast a number greater than 255 to a
byte. But if you'rejust looking to extract the least-significant byte out of
a longer number,try using this formula in your code:
X Mod 256
With X being any integer.
E.g., 137694 Mod 256 = 222.
"Dante" <da******@hotmail.com> wrote in message
news:03****************************@phx.gbl... I'm converting a C# program to VB.net, but i'm having
problems converting a integer to a byte in the same way as the c# program does.
//C# program
int i = 137694;
byte b = (byte) i;
//b returns as value 222
'VB program
dim i as integer = 137694
dim b as byte = CByte(i)
'b returns Overflow Error
I understand that the CByte function only takes values
from 0 - 255, which is why the overflow error, but the c# program casts from int to byte and gets a value of 222.
Anyone know how to get my VB.net app to do this?
.
I figured it out, instead of using mod 256, if I AND the
integer with 255 it works
-10471344 AND 255 = 80
Thanks for your help! -----Original Message-----
Dante,
Then you will need to 'normalize' it with a method other
than the Modoperator. (repeated subtraction or addition comes to
mind).
Or keep that module in C#.
Or turn off the overflow checking.
Hope this helps
Jay
"Dante" <da******@hotmail.com> wrote in message
news:04****************************@phx.gbl... Thanks, that works great, except for negative numbers do
not seem to work.
for example:
-10471344 mod 256 = -176
and in the c# program the value of -10471344 casted to a
byte is equal to 80
>-----Original Message-----
>Well, it seems like the VB.Net way is technically
correct, insofar as you >can't (correctly) cast a number greater than 255 to a
byte. But if you're >just looking to extract the least-significant byte out
of a longer number, >try using this formula in your code:
>
>X Mod 256
>
>With X being any integer.
>
>E.g., 137694 Mod 256 = 222.
>
>
>"Dante" <da******@hotmail.com> wrote in message
>news:03****************************@phx.gbl...
>> I'm converting a C# program to VB.net, but i'm having
>> problems converting a integer to a byte in the same
way as >> the c# program does.
>>
>> //C# program
>> int i = 137694;
>> byte b = (byte) i;
>> //b returns as value 222
>>
>> 'VB program
>> dim i as integer = 137694
>> dim b as byte = CByte(i)
>> 'b returns Overflow Error
>>
>> I understand that the CByte function only takes
values >> from 0 - 255, which is why the overflow error, but
the c# >> program casts from int to byte and gets a value of
222. >> Anyone know how to get my VB.net app to do this?
>
>
>.
>
.
Good catch -- I didn't consider negative numbers as a possible input.
I noticed that 256 - 176 = 80. So, a quick fix is to use an if/then to test
whether the input is positive or negative. If it's negative, use the
following foruma:
256 + Abs (X Mod 256)
For example, if X is -10471344, it returns 80. X Mod 256 is a negative
number, so it's evaluated as 256 + (-176)
There might be a more elegant mathematical solution, but this should get the
job done.
"Dante" <da******@hotmail.com> wrote in message
news:04****************************@phx.gbl... Thanks, that works great, except for negative numbers do
not seem to work.
for example:
-10471344 mod 256 = -176
and in the c# program the value of -10471344 casted to a
byte is equal to 80
-----Original Message-----
Well, it seems like the VB.Net way is technically
correct, insofar as youcan't (correctly) cast a number greater than 255 to a
byte. But if you'rejust looking to extract the least-significant byte out of
a longer number,try using this formula in your code:
X Mod 256
With X being any integer.
E.g., 137694 Mod 256 = 222.
"Dante" <da******@hotmail.com> wrote in message
news:03****************************@phx.gbl... I'm converting a C# program to VB.net, but i'm having
problems converting a integer to a byte in the same way as the c# program does.
//C# program
int i = 137694;
byte b = (byte) i;
//b returns as value 222
'VB program
dim i as integer = 137694
dim b as byte = CByte(i)
'b returns Overflow Error
I understand that the CByte function only takes values
from 0 - 255, which is why the overflow error, but the c# program casts from int to byte and gets a value of 222.
Anyone know how to get my VB.net app to do this?
.
Just saw your solution (damn slow newsservers <g>.) This looks much better.
Good idea.
"Dante" <da******@hotmail.com> wrote in message
news:1f*****************************@phx.gbl... I figured it out, instead of using mod 256, if I AND the
integer with 255 it works
-10471344 AND 255 = 80
Thanks for your help!
-----Original Message-----
Dante,
Then you will need to 'normalize' it with a method other
than the Modoperator. (repeated subtraction or addition comes to
mind).
Or keep that module in C#.
Or turn off the overflow checking.
Hope this helps
Jay
"Dante" <da******@hotmail.com> wrote in message
news:04****************************@phx.gbl... Thanks, that works great, except for negative numbers do
not seem to work.
for example:
-10471344 mod 256 = -176
and in the c# program the value of -10471344 casted to a
byte is equal to 80
>-----Original Message-----
>Well, it seems like the VB.Net way is technically
correct, insofar as you
>can't (correctly) cast a number greater than 255 to a
byte. But if you're
>just looking to extract the least-significant byte out of a longer number,
>try using this formula in your code:
>
>X Mod 256
>
>With X being any integer.
>
>E.g., 137694 Mod 256 = 222.
>
>
>"Dante" <da******@hotmail.com> wrote in message
>news:03****************************@phx.gbl...
>> I'm converting a C# program to VB.net, but i'm having
>> problems converting a integer to a byte in the same way as
>> the c# program does.
>>
>> //C# program
>> int i = 137694;
>> byte b = (byte) i;
>> //b returns as value 222
>>
>> 'VB program
>> dim i as integer = 137694
>> dim b as byte = CByte(i)
>> 'b returns Overflow Error
>>
>> I understand that the CByte function only takes values >> from 0 - 255, which is why the overflow error, but the c#
>> program casts from int to byte and gets a value of 222. >> Anyone know how to get my VB.net app to do this?
>
>
>.
>
.
Dante,
Doh! forgot about anding with 255. :-)
Jay
"Dante" <da******@hotmail.com> wrote in message
news:1f*****************************@phx.gbl... I figured it out, instead of using mod 256, if I AND the
integer with 255 it works
-10471344 AND 255 = 80
Thanks for your help!
-----Original Message-----
Dante,
Then you will need to 'normalize' it with a method other
than the Modoperator. (repeated subtraction or addition comes to
mind).
Or keep that module in C#.
Or turn off the overflow checking.
Hope this helps
Jay
"Dante" <da******@hotmail.com> wrote in message
news:04****************************@phx.gbl... Thanks, that works great, except for negative numbers do
not seem to work.
for example:
-10471344 mod 256 = -176
and in the c# program the value of -10471344 casted to a
byte is equal to 80
>-----Original Message-----
>Well, it seems like the VB.Net way is technically
correct, insofar as you
>can't (correctly) cast a number greater than 255 to a
byte. But if you're
>just looking to extract the least-significant byte out of a longer number,
>try using this formula in your code:
>
>X Mod 256
>
>With X being any integer.
>
>E.g., 137694 Mod 256 = 222.
>
>
>"Dante" <da******@hotmail.com> wrote in message
>news:03****************************@phx.gbl...
>> I'm converting a C# program to VB.net, but i'm having
>> problems converting a integer to a byte in the same way as
>> the c# program does.
>>
>> //C# program
>> int i = 137694;
>> byte b = (byte) i;
>> //b returns as value 222
>>
>> 'VB program
>> dim i as integer = 137694
>> dim b as byte = CByte(i)
>> 'b returns Overflow Error
>>
>> I understand that the CByte function only takes values >> from 0 - 255, which is why the overflow error, but the c#
>> program casts from int to byte and gets a value of 222. >> Anyone know how to get my VB.net app to do this?
>
>
>.
>
.
Hi Jay,
ROFL - I didn't want to say anything but I was surprised. ;-)
Regards,
Fergus
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