Hi there,
The easiest way to achieve your goal is to convert your INT into an
eight character long string first, and then convert your string in the
datetime format.
As an example : SELECT CONVERT(DATETIME, CONVERT(CHAR(8), 20070824))
Elsewhere, it is a bit complicated, as the DateTime format is based on
the difference in days from 1900/01/01. Thus, you have to use a quite
heavy function as leap years are not regular. All the functions I
tried have bad performance compared to the double conversion.
Enjoy,
Cédric Del Nibbio
MCT
MCDBA SQL Server 2000
MCITP Database Administrator SQL Server 2005
MCSD .NET
http://cedric-delnibbio-sql.blogspot.com
On 24 août, 00:41, "rdraider" <rdrai...@sbcglobal.netwrote:
I can't seem to find a way to convert an INT type in the form of YYYYMMDDto
an actual date form of mm/dd/yyyy
>
Can anyone pointt me in the right direction?
>
Thanks
