merging dictionaries

v13tn1g

so basically i've written most of the code the only problem that i'm having is that the output that it gives me will not return a key with a different type. It will either return me keys with only int, or only str..for example

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 def merge_dictionaries(d1, d2):

    '''Return a dictionary that is the result of merging the two given 

    dictionaries. In the new dictionary, the values should be lists. If a key 

    is in both of the given dictionaries, the value in the new dictionary should

    contain both of the values from the given dictionaries, even if they are the 

    same. '''
 
    d3 = {}

    for c in d1:

        if c in d2:

            d3[c] = [d1[c], d2[c]]

        else:

            d3[c] = [d1[c]]

    print d3

how i tested it is with:

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 merge_dictionaries({ 1 : 'a', 2 : 9, -8 : 'w'}, {2 : 7, 'x' : 3, 1 : 'a'})
 
 

and the out put is:

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{-8: ['w'], 1: ['a', 'a'], 2: [9, 7]}

why doesn't it print out the 'x' key and value??

bvdet

Because d2 has a key that d1 does not have. You only iterate on d1, so key 'x' is never seen.

-BV

bvdet

Take a look at this:

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 import copy
 
def merge_dictionaries(d1, d2):

    d3 = copy.copy(d1)

    for key in d2:

        if key in d3:

            d3[key] = [d3[key], d2[key]]

        else:

            d3[key] = [d2[key]]

    return d3
 
dd1 = { 1 : 'a', 2 : 9, -8 : 'w'}

dd2 = {2 : 7, 'x' : 3, 1 : 'a'}

print merge_dictionaries(dd1, dd2)

v13tn1g

in this case you imported copy, what is that?

bvdet

Quote:

Originally Posted by v13tn1g

in this case you imported copy, what is that?

copy.copy makes a shallow copy of an object. From Python documentation:
"A shallow copy constructs a new compound object and then (to the extent possible) inserts references into it to the objects found in the original."

This will do the same thing:

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d3 = dict(d1.items())

merging dictionaries

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