finding filename in log file

cooolsson · #1 October 6th, 2008, 12:31 PM

I have a log file with this line
lisa.sm.luth.se - - [15/Aug/2005:02:42:12 +0200] "GET //csee/csn/include/div.cfg HTTP/1.0" 200 447 "-" "-"
I want to extract the filename between GET and HTTP. Is there a function i can use. I have heard split works but i have no idea. Thanks in advance.

bvdet · #2 October 6th, 2008, 02:28 PM

Here's two ways - re and string slicing.

Expand|Select|Wrap|Line Numbers

 import re
 
s = 'lisa.sm.luth.se - - [15/Aug/2005:02:42:12 +0200] "GET //csee/csn/include/div.cfg HTTP/1.0" 200 447 "-" "-"'
 
patt = re.compile(r"GET (.+) HTTP")

m = patt.search(s)

if m:

    print m.group(1)
 
print s[s.index("GET ")+4:s.index(" HTTP")]

finding filename in log file

re: finding filename in log file

/bytes/development

/bytes/it

/bytes/about