Jyotirmoy Bhattacharya <jmoy.matecon@gmail.comwrote:
Quote:
I'm a newcomer to Python. I have just discovered nested list
comprehensions and I need help to understand how the if-clause
interacts with the multiple for-clauses. I have this small program:
>
def multab(n):
print 'multab',n
return [n*i for i in range(5)]
>
print [(m,n) for m in range(5) for n in multab(m) if m>2]
>
It produces the output:
multab 0
multab 1
multab 2
multab 3
multab 4
[(3, 0), (3, 3), (3, 6), (3, 9), (3, 12), (4, 0), (4, 4), (4, 8), (4,
12), (4, 16)]
>
I was wondering if there is some way to write the if-clause so that it
is 'hoisted' out of the inner loop and the multab function is not
called at all for m=0,1,2. That would seem to be important if multab
were an expensive function.
Sure, just place the if clause where it needs to apply (between the two
for clauses) [apart from the fact that this example is best expressed by
using range(3,5), as somebody already said;-)].
Generally, the semantics of:
x = [<exprfor <F1if <I2for <F3>]
are exactly those of
x = []
for <F1:
if <I2:
for<F3:
x.append(expr)
and similarly for other mixes of for and if clauses (except that the
first clause must always be a for clause) -- you can always, simply and
mechanically conceptually translate them into an equivalent nest of for
and if statements, ending in a somelist.append(...) [where somelist may
be a "temporary anonymous" list if you're just going to use the listcomp
further rather than just assigning it to a name].
Alex
