Creating a standard log file that is accessible by all other files

indiarocks

Just a basic question, I want to create a standard log file API and want that API to be shared by all my other python files.
For eg. I have file1 which creates a file handle and hands it over to say log.py

Now say I have file2, and it needs to write into the same log file, how do I achieve this and what is the best way of doing it ?

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-------

File1:

--------
 
log_file = file('out.log',"w")

log_obj = log.log(log_file)
 
log_obj.write("Hello world from File 1") 
 
----------

log.py 

----------

class log:

      def __init__(self,log):

         self.log = log 

       def write(self,message):

            self.log.write(message)

----------

File 2: 

----------
 
from log import * 

log.write("message from file2")

This obviously will not work because I am passing a str object instead of log instance.

Any tips ?

indiarocks

Tried implementing the following method and it seems to work. Not sure if it's a good way to do it.

<code>

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file1.py 

# Declare a global list which can be accessible by other files 

log_list = []
 
def func1():

   global log_list 

   log_file = file('abc.out',"w")

   log_list.append(log_file)
 
</code>
 
<code> 

File2.py 

import log 

import file1 
 
file1.func1() 

log.write("Hello World ")

</code> 
 
<code> 

log.py 

from g import log_list 
 
def write(message):

       log_list[0].write(message) 

</code>

So basically what happens is that when you run file2, file1 creates a log file which can be shared by other files. This one worked because log_list is a list which is mutable and that is imported by log.py. I thought that even log file handlers where mutable, but that didn't work for some reason. And putting that log_file handle within a list seemed to solve the issue.

bvdet

Quote:

Originally Posted by indiarocks

Tried implementing the following method and it seems to work. Not sure if it's a good way to do it.

<code>

file1.py
# Declare a global list which can be accessible by other files
log_list = []

def func1():
global log_list
log_file = file('abc.out',"w")
log_list.append(log_file)

</code>

<code>
File2.py
import log
import file1

file1.func1()
log.write("Hello World ")
</code>

<code>
log.py
from g import log_list

def write(message):
log_list[0].write(message)
</code>

So basically what happens is that when you run file2, file1 creates a log file which can be shared by other files. This one worked because log_list is a list which is mutable and that is imported by log.py. I thought that even log file handlers where mutable, but that didn't work for some reason. And putting that log_file handle within a list seemed to solve the issue.

I see you are trying to use code tags. Good, except use square brackets '[ ]' instead of '< >'.

Why not:

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 # file1.py
 
log_file_name = r'H:\TEMP\log.txt'
 
............................................................
 
# log_file.py
 
import file1
 
# open log file

f = open(file1.log_file_name, 'a')

.............................................

ghostdog74

actually you don't to create your own. Python has a logger module. Unless of course, you have other requirements.

indiarocks

Quote:

Originally Posted by bvdet

I see you are trying to use code tags. Good, except use square brackets '[ ]' instead of '< >'.

Why not:

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 # file1.py
 
log_file_name = r'H:\TEMP\log.txt'
 
............................................................
 
# log_file.py
 
import file1
 
# open log file

f = open(file1.log_file_name, 'a')

.............................................

In this case if I have my program spread across 15 files, I need to explicitly open each of the files in these 15 files. To avoid that I created a general log function which can be imported by other files and they can directly use as log(msg)

bvdet

Quote:

Originally Posted by indiarocks

In this case if I have my program spread across 15 files, I need to explicitly open each of the files in these 15 files. To avoid that I created a general log function which can be imported by other files and they can directly use as log(msg)

Gotcha. For some reason I thought you were just needing the file name. Is it working well?

bartonc

Quote:

Originally Posted by indiarocks

In this case if I have my program spread across 15 files, I need to explicitly open each of the files in these 15 files. To avoid that I created a general log function which can be imported by other files and they can directly use as log(msg)

They're called 'tags', so (if you know HTML) in makes sense to use
<code>
</code>
But on this site, we use [code] and the next one has the forward slash (but if I put it here it will disappear. You can use the # button at the top of the editor.