DOTALL not working as expected

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Hi all,
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using the "re" module of Python (2.3 and 2.4), I tried the following:
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import re
print re.sub('X.*?Y', 'Z', 'Xab\ncdY', re.DOTALL)
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I wanted to replace
Xab
cdY
by a single "Z", but the "." in the pattern does not match the
included "\n".
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When using the pattern "X(.|\n)*?Y" (explicity including "\n"
in the set of "any character") I get the wanted result.
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My fault or a bug in the module?
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Thanks
-stefan-

Just noticed, that it works when *compiling* the pattern:
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import re
p = re.compile('X.*?Y', re.DOTALL)
print re.sub(p, 'Z', 'Xab\ncdY')
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Still the question - my fault or a bug?

Stefan Palme wrote: >
Your fault. According to the documentation [1], the re.sub function takes
a count as a fourth argument, not the compilation flags.
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[1] http://docs.python.org/lib/node46.html
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Cheers,