If you look at the OP's question he does not say that he wants the variables
inside the function to be loaded into the $_SESSION array, therefore your
answer is not appropriate.
--
Tony Marston
http://www.tonymarston.net
"Phil Palmieri" <google@page12.com> wrote in message
news:972d7ea.0410290437.79f9cda2@posting.google.co m...[color=blue]
> This is also a messy solution, but it does work.. Inside your
> function set the 'global' variable to a session ie:
>
> function some_function(){
> blah blah blah
>
> $_SESSION[some_function] = $the_global_var;
>
>
> }
>
> Phil
>
> "Tony Marston" <tony@NOSPAM.demon.co.uk> wrote in message
> news:<clskdd$anl$1$8302bc10@news.demon.co.uk>...[color=green]
>> "Deane Barker" <deane@slingandrock.com> wrote in message
>> news:3ee9b2f.0410281851.4b27acb6@posting.google.co m...[color=darkred]
>> >I have a function that selects a file to include, then includes is.
>> > The file is including within the function, like so:
>> >
>> > function include_file($file_name)
>> > {
>> > [lots of logic here to figure out the path...]
>> > require $file_name;
>> > return;
>> > }
>> >
>> > My problem is that the file gets included *within* the function, so
>> > all the code in the file inherits the function's scope. Any variables
>> > declared in the include file are not global -- they're local to that
>> > function.
>> >
>> > Is there any way around this? Is there anything I can put in the
>> > included file or in the function to make sure that variables declared
>> > within it are global? (I can't just reference the variables before
>> > the require, because I have no way of knowing what's in the include
>> > file.)[/color]
>>
>> Use the function to determine the filename, but instead of include()ing
>> it
>> within the function just return the name to the calling script. When the
>> calling script issues the include() any variables will then be within the
>> scope of that script, not the function.
>>
>> Easy when you know how.[/color][/color]
