using next() on multidimensional arrays

phpnewbie26 · #1 June 19th, 2009, 03:04 PM

So I'm trying to use the next() function on my array within my multidimensional array. It looks like this:

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Array(

   testA=> Array(

                 phaseA=>5,

                 phaseB=>4,

                 total=>9

              ),

  testB=>Array(

                 phaseA=>3,

                 phaseB=>3,

                 total=>6

              )

      )

so I'm trying to use the next function in the array with the phases to see if the next one is "total". What I currently have so far is this

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if(next($sub2)=='total'){

        echo "next";

        }

But for some reason, it never goes into this loop.=/ Please help me find out where I went wrong. Thanks in advance.

Atli · #2 June 19th, 2009, 05:04 PM

Hi.

The next() function returns the value of the element, not the key.

If you want to match against the key, you need to use the key() function.
Like:

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do {

    if(key($array) == 'total') {

        echo "Total = " . current($array);

    }

} while(next());

In that scenario, however, you could just as well do:

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if(isset($array['total']) {

    echo 'Total = '. $array['total'];

}

using next() on multidimensional arrays

re: using next() on multidimensional arrays

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