ORDER BY variable DESC

ArizonaJohn

Hello,

I would like the code below to sort the echoed output by votes_up descending. I have added "ORDER BY votes_up DESC" to both queries, but the echoed output is still not sorting. Any ideas why it is not working?

Thanks in advance,

John

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 $result = mysql_query("SHOW TABLES FROM feather") 

or die(mysql_error()); 
 
while(list($table)= mysql_fetch_row($result))

{

  $sqlA = "SELECT COUNT(*) FROM `$table` WHERE `site` LIKE '$entry' ORDER BY votes_up DESC";

  $resA = mysql_query($sqlA) or die("$sqlA:".mysql_error());

  list($isThere) = mysql_fetch_row($resA);

  if ($isThere)

  {

     $table_list[] = $table;

  }

}
 
foreach ($table_list as $table) { 

    $sql = "SELECT votes_up FROM `$table` WHERE `site` LIKE '$entry' ORDER BY votes_up DESC"; 

    $sql1 = mysql_query($sql) or die("$sql:".mysql_error());

   while ($row = mysql_fetch_assoc($sql1)) {

       echo $table . ': "' . $row['votes_up'] . " for $entry from $table\"<br />";

   } 

}

dlite922

you need to troubleshoot when you're code is not working and is not producing an error that we could understand.

why don't you echo your $sql variables, take those and plug them into a mysql client, run the query manually to see if the output is even what you're looking for.

Dan

yangyucn

so confused, i dont know what u r going to do...

if u wanto sort the result, u should code like this:

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$sql = "SELECT * 

        FROM `table_name` 

        WHERE `id` = '".$id."' 

        ORDER BY `timestamp` DESC  ";

$query = mysql_query($sql);

while ($rt = mysql_fetch_assoc($query)){

    echo '<pre>';

    print_r ($rt);

    echo '</pre>';

}

ORDER BY variable DESC

re: ORDER BY variable DESC

re: ORDER BY variable DESC

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