Show only last word in a parameter

I have a parameter $name that contavins e.g. "Turn left at Blooming
Grove Turnpike/Quassaic Turnpike/RT-94 Continue to follow RT-94".
I just want to have the last word. The number of words will be different
each time.

I looked at http://be.php.net/manual/en/book.strings.php but I either
did not see it or I am looking at the wrong place (or both)

houghi
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re: Show only last word in a parameter

houghi wrote:As often happens, I found it right after posting, evin if I was looking
for it for a long time:

$name="your text with words. try to find the last word using several
spaces before the last word gsvdfg5412f_tw4t=agast3)(@35.\n";
preg_match("/(?<=\040)([^\s]+?)$/",trim($name),$matches);
$name = $matches[0];

Found it on http://www.programmingtalk.com/showthread.php?t=12649

houghi
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re: Show only last word in a parameter

houghi wrote:Well, you could use something like:

$name = trim($name); // Strip leading/trailing white space
$pos = strrpos($name, ' '); Find the last space
if ($pos === false) // If there is none
$word = $name; // Then only one word
else
$word = substr($name, $pos+1); // Get everything following the space
echo $word;

Assuming, of course, you always have a space as a word separator.

--
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Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
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re: Show only last word in a parameter

Jerry Stuckle wrote:It is, thanks for the feedback.

houghi
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