A little help with isset, in_array

I am trying to search within an array to see if there is a match, but I
can't get my head around these functions which are supposed to return
TRUE or FALSE.
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First I get a list of values from a database and build an array with it
with numerical indexes.
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When I finally do a comparison using both ...
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in_array($item_link_md5, $real_id_array);
isset($real_id_array[$item_link_md5]);
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I get a number as it's return value and it seems to be the total number
of values in the array, not a simple TRUE or FALSE.
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Where am I going wrong here?
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What's your actual code? In both of these examples you're just throwing
away the results of the function calls.
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Jerry Stuckle wrote:>
This is the basic code ...
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// build array from db results
while ($id_array = mysql_fetch_array($sql_id_matching_result)) {
$real_item_id_array[] = $id_array['item_id'];
}
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$item_link_md5 = 'test_var';
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if (isset($real_id_array[$item_link_md5])) {
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// do stuff here.
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}
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Vernon Wenberg III wrote:>
EDIT: *real_item_id_array in the if statement.
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Vernon Wenberg III wrote:>
OK, this is checking to see if $real_id_array['test_var'] is set.
However, you added them with default indexes, so what you have in the
array is:
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$real_id_array[0]
$real_id_array[1]
$real_id_array[2]
$real_id_array[3]
etc.
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So isset() will never return true.
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What are you TRYING to do?
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Jerry Stuckle wrote:>>>>>>>>>>>
I'm trying to compare values from the DB which are now in an array to
the a new value to find out if the new value exists in the DB.
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Thank you for the explanation. I've gotten it to work now after you
pointed out the creation of my array was where I went wrong. I thought
that isset was just giving me quirky results.
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Much thanks.