On Sat, 27 Oct 2007 23:44:56 +0200,
leonardodiserpierodavinci@gmail.com
<leonardodiserpierodavinci@gmail.comwrote:
Quote:
Hi. Sorry for what is perhaps a neophyte question: is it possible to
pass a variable to a PHP script from inside another PHP piece of code?
>
For instance, the file test.php (which of course resides on a
webserver that supports PHP) is as such:
>
[some HTML code...]
<?php
echo("<i>the variable abc contains " . $_GET['abc'] . "</i>");
?>
[some more HTML code...]
>
and if I open this file directly i.e. by typing test.php?abc=888 in
the URL line of a web browser, I correctly get the message "the
variable abc contains 888" in italic, surrounded by the HTML content.
>
Now, let's say that I want to include all this content in another
file, index.php.
I tried to call it as such in index.php
>
[other HTML...]
<?php
include "test.php?abc=888";
?>
[yet other HTML...]
>
which is not the correct way as it gives the following error:
>
Warning: main(l/test.php?abc=888) [function.main]: failed to open
stream: No such file or directory in /home/www/index.php on line 52
Warning: main() [function.include]: Failed opening 'l/test.php?
abc=888' for inclusion (include_path='.:/usr/share/php:/usr/share/
pear') in /home/www/index.php on line 52
>
How should I call the file?
Thanks in advance for any hint!
The $_GET array is available to all scipts, _provided_ you use the file
system to include the file, and not by http some newcomers seem to do. So:
URL:
test.php?foo=bar
test.php:
<?php
$check = 'hello';
include './include.php';
?>
include.php
<?php
var_dump($_GET);
echo $check;
?>
... will correctly show the $_GET array and the $check variable.
--
Rik Wasmus
