caller has no way knowing whether the function will modify the argument?

Summercool

Guest

Posts: n/a

#1: Sep 27 '07

Is it true that the caller has no way to know whether the function it
is calling uses

function foo($a)

or

function foo(&$a)

so the caller never knows whether it is "pass by value" or "pass by
reference" and so won't know whether the argument can be modified or
not?

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