order by file name readdir()

Hello!

I have written such function...

Unfortunately images are not sorted by filename and I don`t know why.

I have such files placed in subfolder:

2005_11_17_koncert_Riverisde_w_Poznaniu_1.jpg
2005_11_17_koncert_Riverisde_w_Poznaniu_2.jpg
2005_11_17_koncert_Riverisde_w_Poznaniu_3.jpg
2005_11_17_koncert_Riverisde_w_Poznaniu_4.jpg
2005_11_17_koncert_Riverisde_w_Poznaniu_5.jpg
2005_11_17_koncert_Riverisde_w_Poznaniu_6.jpg
2006_01_22_wizyta_Panstwa_Rakowskich.jpg
2006_01_22_wizyta_u_babci_Ali.jpg

Even if I replaced the file names into

a2005_11_17_koncert_Riverisde_w_Poznaniu_1.jpg
a2005_11_17_koncert_Riverisde_w_Poznaniu_2.jpg
a2005_11_17_koncert_Riverisde_w_Poznaniu_3.jpg
a2005_11_17_koncert_Riverisde_w_Poznaniu_4.jpg
a2005_11_17_koncert_Riverisde_w_Poznaniu_5.jpg
a2005_11_17_koncert_Riverisde_w_Poznaniu_6.jpg
b2006_01_22_wizyta_Panstwa_Rakowskich.jpg
b2006_01_22_wizyta_u_babci_Ali.jpg

it still gives me the wrong order.

Can you help me fixing it?
-------------------------------------------------------------------------------

function zczytaj_zdjecia_z_folderu($sciezka)
{

error_reporting(0);
$handle=opendir($sciezka);

if ($handle=="")
{
echo "<br>";
echo "<p align=\"center\">Brak plikow na dysku <b>".$sciezka."</b></p>";
$ilosc_zdjec_w_folderze=-1;
}
else
{
$licznik=0;
while (false !== ($file = readdir($handle)))
{
if ($file <"." && $file <"..")
{
$licznik++;
if ( (substr(strtoupper($file),strlen($file)-4,4)==".GIF") ||
(substr(strtoupper($file),strlen($file)-4,4)==".JPG") ||
(substr(strtoupper($file),strlen($file)-4,4)==".JPEG") ||
(substr(strtoupper($file),strlen($file)-4,4)==".BMP") ||
(substr(strtoupper($file),strlen($file)-4,4)==".PNG")
)


list($width, $height, $type, $attr) = getimagesize($sciezka.$file);

$item=$width/160;
$width_new=160;
$height_new=intval($height/$item);

if ($height_new>100)
{
$item=$height/100;
$height_new=100;
$width_new=intval($width/$item);
}


//najlepiej dobrany rozmiar to height=100; width=160;
{
?>
<a href="#" OnClick="funkcja('<?=$sciezka.$file; ?>');"><img
alt="<?=$file; ?>" src="<?=$sciezka."/".$file; ?>" border="1"
height="<?=$height_new; ?>" width="<?=$width_new; ?>"></a>
<?
if ($licznik==5) { echo "<br><br>"; $licznik=0;}
error_reporting(1);
// break;
}
}
else
{

}
}
}
error_reporting(1);

return (0);
}


----------------------------------------------------------------------------------------

re: order by file name readdir()

MZ schreef:From: http://www.php.net/readdir
Returns the filename of the next file from the directory. The filenames
are returned in the order in which they are stored by the filesystem.

So you still have to add code that sorts the filenames by name..

eg:

$filenames = array();
while ($filename = readdir($dir)) {
$filenames[] = $filename;
}

sort($filenames);

foreach($filename in $filenames) {
echo $filename . '<br/>';
}

--
Tim Van Wassenhove <url:http://www.timvw.be/>

re: order by file name readdir()

On Apr 15, 8:27 am, Tim Van Wassenhove <t...@users.sourceforge.net>
wrote:Alternatively you can use scandir() and specify the sorting_order
parameter:

<http://www.php.net/scandir>

re: order by file name readdir()

Uzytkownik "Tim Van Wassenhove" <timvw@users.sourceforge.netnapisal w
wiadomosci news:LqOdnYK4zsK_h7_bnZ2dnUVZ8sSrnZ2d@scarlet.biz. ..
Thank you very much for help..

There is little error in the code. It should be:

foreach($filenames in $file) {
echo $file . '<br/>';
}


Cheers, thanx, hugs
Marcin

re: order by file name readdir()

U¿ytkownik "MZ" <marcinzmyslowski@poczta.onet.plnapisa³ w wiadomo¶ci
news:evtrkn$618$1@news.onet.pl...Sorry it should be::

foreach($filenames as $file)
{
echo $file . '<br/>';
}