command-line PHP problem

I am trying to simply pipe in 2 very small commands and not have to
create a PHP script to do this:

However, I do not have the "-r" option in PHP 4.3.9, and I would think
that I would, but why not? Here is all I have to work with:

What should I do?

Thanx
Phil

re: command-line PHP problem

comp.lang.php wrote:Thats interesting because I do.

SilverNail:~# php -hv
Usage: php [options] [-f] <file [args...]
php [options] -r <code [args...]
php [options] [-- args...]
-a Run interactively
-c <path|<file Look for php.ini file in this directory
-n No php.ini file will be used
-d foo[=bar] Define INI entry foo with value 'bar'
-e Generate extended information for debugger/profiler
-f <file Parse <file.
-h This help
-i PHP information
-l Syntax check only (lint)
-m Show compiled in modules
-r <code Run PHP <code without using script tags <?..?
-s Display colour syntax highlighted source.
-v Version number
-w Display source with stripped comments and whitespace.
-z <file Load Zend extension <file.

args... Arguments passed to script. Use -- args when first
argument
starts with - or script is read from stdin

SilverNail:~# php -v
PHP 4.3.9-2 (cli) (built: Dec 2 2004 05:45:27)
Copyright (c) 1997-2004 The PHP Group
Zend Engine v1.3.0, Copyright (c) 1998-2004 Zend Technologies
SilverNail:~#

re: command-line PHP problem

Dave Kelly wrote:Any ideas as to why?

re: command-line PHP problem

You might be running a php compiled in CGI SAPI mode. Is there another
php on your system that you might be able to use? For example,
/usr/bin/php might be the CGI version, and /usr/local/bin/php might be
the CLI one.

In any case, you can still use your CGI mode php if you write the
commands into PHP's stdin:

echo '<? phpinfo() ?>' | php

comp.lang.php wrote:

re: command-line PHP problem

petersprc wrote:Sorry apparently there is only /usr/local/bin/php and that does not
offer the -r option; how can I tell it is in CGI SAPI mode?
Thanx! That did the trick perfectly!!

Phil