comparision of 32 bit signed numbers

raghavendrap

Hello friends,
I need help in comparision of 32 bit signed numbers.
I am generating random signed numbers using some logic & when i am doing addition of two numbers i am getting maximum value 0X80000000.
how to avoid this?
Example:#

Expand|Select|Wrap|Line Numbers

 
use strict ;
 
my $a;

my $b;

my $result;
 
$range = 2**31; # 2^(n-1): n=32

 $min = -2**31; #lowest integer

 $val= int(rand($range)) + $min;

 print "$val\n"
 
  $a = $val;

  $b = $val;

  $result = $a+$b;

In the above example, $result will overflow i.e exceeds the range 0x8000000 after addition of two signed numbers, & am getting result as 0x8000000 only, in order to avoid this what i need to do?

Thanks
Raghavendra

crazy4perl

Quote:

Originally Posted by raghavendrap

Hello friends,
I need help in comparision of 32 bit signed numbers.
I am generating random signed numbers using some logic & when i am doing addition of two numbers i am getting maximum value 0X80000000.
how to avoid this?
Example:#

Expand|Select|Wrap|Line Numbers

 
use strict ;
 
my $a;

my $b;

my $result;
 
$range = 2**31; # 2^(n-1): n=32

 $min = -2**31; #lowest integer

 $val= int(rand($range)) + $min;

 print "$val\n"
 
  $a = $val;

  $b = $val;

  $result = $a+$b;

In the above example, $result will overflow i.e exceeds the range 0x8000000 after addition of two signed numbers, & am getting result as 0x8000000 only, in order to avoid this what i need to do?

Thanks
Raghavendra

I dont know but its working fine for me

val := -1149894656
result := -2299789312

raghavendrap

hey man i have just posted an example in order understand my question,
if overflows what to do ? & if it in hexadecimal format how to compare with >0 or <0, i am getting the wrong result

comparision of 32 bit signed numbers

re: comparision of 32 bit signed numbers

re: comparision of 32 bit signed numbers

Similar Perl bytes

/bytes/development

/bytes/it

/bytes/about